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erica [24]
3 years ago
5

You have two exponential functions. One function has the formula g(x) = 5 ^x . The other function has the formula h(x) = 5^-x .

Which option below gives formula for k(x) = (g - h)(x)?
Mathematics
2 answers:
lidiya [134]3 years ago
5 0

Answer:

The required result is  k(x)=\frac{5^{2x}-1}{5^x}

Step-by-step explanation:

Given : You have two exponential functions. One function has the formula g(x) = 5 ^x . The other function has the formula h(x) = 5^{-x} .

To find : Which gives formula for  k(x)=(g-h)(x)?

Solution :

Let g(x) = 5 ^x ....(1)

h(x) = 5^{-x} .....(2)

We have to find, k(x)=(g-h)(x)

We can write it as,

k(x)=g(x)-h(x) ......(3)

Now, substitute the values from (1) and (2) in equation (3),

k(x)=5^x-(5^{-x})

Open the parenthesis on right hand side of equation, we get

k(x)=5^x-5^{-x}

Now, Using x^{-a}=\frac{1}{x^a}

k(x)=5^x-\frac{1}{5^x}

Taking LCM,

k(x)=\frac{5^{2x}-1}{5^x}

Therefore, The required result is  k(x)=\frac{5^{2x}-1}{5^x}

Shkiper50 [21]3 years ago
4 0
We are given with two functions here: h(x) is 5^-x and g(x) is 5^x . we are asked in the problem to determine the value of the expression (g-h)(x). In this case, we just have to employ subtraction to the given functions. That is 

(g-h)(x) = 5^x - 5^-x
             = 5^x -1/5^x
             = (5^2x -1)/5^x


 
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Answer:

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Step-by-step explanation:

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What is the factorization of the polynomial below?<br><br> x^3-4x^2+45x
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If you solve the quadratic equation inside the parenthesis using the quadratic formula, the roots are imaginary. Therefore, the quadratic equation is already a prime polynomial. 

The final answer is x(x² - 4x + 45).
3 0
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Read 2 more answers
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