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lapo4ka [179]
3 years ago
5

Triangle Q S R is shown. Angle Q S R is a right angle. Altitude s is drawn from point S to point T on side Q R to form a right a

ngle. Side Q S is labeled r and side W R is labeled q. The length of Q T is 10 and the length of R T is 4. What is the value of q? 4 StartRoot 5 EndRoot 2 StartRoot 14 EndRoot 20 StartRoot 5 EndRoot
Mathematics
2 answers:
Readme [11.4K]3 years ago
5 0

Answer:

q = 2√14

Step-by-step explanation:

got it right on test

Neko [114]3 years ago
4 0

*The diagram is in the attachment

Answer:

q = 2√14

Step-by-step explanation:

To determine the value of q, apply the leg rule/geometric mean theorem, which is:

Hypotenuse/leg = leg/part

Hypotenuse = 10 + 4 = 14

Leg = q

Part = 4

Plug in the values into the equation:

14/q = q/4

Cross multiply

q*q = 14*4

q² = 56

q = √56

q = √(4*14)

q = 2√14

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The average lifetime of a certain new cell phone is 3.4 years. The manufacturer will replace any cell phone failing within three
melisa1 [442]

Answer:

68% of these phones last 3.87 years.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

The average lifetime of a certain new cell phone is 3.4 years.

This means that m = 3.4, \mu = \frac{1}{3.4} = 0.2941

So

P(X \leq x) = 1 - e^{-0.2941x}

68% of these phones last how long (in years)?

This is x for which:

P(X \leq x) = 0.68

P(X \leq x) = 1 - e^{-0.2941x}

Then

0.68 = 1 - e^{-0.2941x}

e{-0.2941x} = 0.32

\ln{e{-0.2941x}} = \ln{0.32}

-0.2941x = \ln{0.32}

x = -\frac{\ln{0.32}}{0.2941}

x = 3.87

68% of these phones last 3.87 years.

4 0
3 years ago
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