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4 years ago

How should the system administrator resolve the issue?

Engineering

1 answer:

Hunter-Best [27]4 years ago

4 0

Answer:

Option B

Select the Marketing User checkbox in the user record

Explanation:

The user settings may limit users who can view and set up advanced campaigns. In case there's no keyboard shortcut already programmed to create a new campaign and also the button for creating new campaign isn't visible, the best way to go about it is by selecting the marketing user checkbox in the user record and create a new campaign,

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The difference between ideal voltage source and the ideal current source

DENIUS [597]

An ideal voltage source provides no energy when it is loaded by an open circuit (i.e. an infinite impedance), but approaches infinite energy and current when the load resistance approaches zero (a short circuit). ... An ideal current source has an infinite output impedance in parallel with the source.

5 0

4 years ago

Read 2 more answers

Determine the specific volume of superheated water vapor at 15 MPa and 350°C, using a. The ideal-gas equation Answer: 0.01917 m3

ollegr [7]

Answer:

specific volume by ideal gas equation = 0.01917 m³/kg

specific volume by compressibility chart = 0.01246 m³/kg

specif volume by super heated stream table is 0.0114810 m³/kg

Explanation:

given data

temperature T = 350°C = 623 K

pressure P = 15 MPa = 15000 kPa

to find out

specific volume by ideal-gas equation ,generalized compressibility chart and steam tables

solution

we will apply here ideal gas equation that is

specific volume = $\frac{R*T}{P}$ ..............1

here P is pressure and T is temperature and R is gas constant i.e 0.4615 kJ/kg-K

specific volume = $\frac{0.4615*623}{15000}$

specific volume = 0.01917 m³/kg

and

by the compressibility chart

critical pressure of water Pcr = 22.06 Mpa

and critical temperature of water Tcr = 647.1 K

reduced pressure will be = $\frac{P}{Pcr}$

reduced pressure = $\frac{15}{22.06}$ = 0.68 Mpa

and

reduced temperature will be = $\frac{T}{Tcr}$

reduced pressure = $\frac{623}{647.1}$ = 0.963 K

so by compressibility chart pressure 0.68 Mpa and temperature 0.963 K

compressibility factor Z is 0.65

specific volume = compressibility factor Z × ideal specific volume

specific volume = 0.65 × 0.01917

specific volume = 0.01246 m³/kg

and

by the steam table

use here super heated stream table for

pressure = 15 Mpa

ans temperature = 350°C

specif volume by super heated stream table is 0.0114810 m³/kg

6 0

4 years ago

What is the basic definition of design?

torisob [31]

A design is a plan or specification for the construction of an object or system or for the implementation of an activity or process, or the result of that plan or specification in the form of a prototype, product or process. The verb to design expresses the process of developing a design.

8 0

4 years ago

A 25 kg iron block initially at 280°C is quenched in an insulated tank that contains 100 kg of water at 18°C. Assuming the water

defon

Answer: water at 18°C, w cw = 4.18 kJ/kg∙°C; at 27oC, Cfe = 0.554 kJ/kg∙°C. (Note that we could also have the following units for the heat capacities: kJ/kg∙K.) Assuming that the heat capacities are constant we have the following

The final temperature of the iron and the water will be the same: Tfe,2 = Tw,2 = T2. Substituting T2 for Tfe,2 and Tw,2, and solving for T2 gives the following result for the final temperature.

T2= ((Mw. Cw.T1w) + (Mfe.Cfe. T1fe))/((Mw.Cw) + (Mfe.Cfe))...equ 1

Where Me= mass of water= 100kg, Mfe =mass of iron = 25kg, T1fe = temp of iron before= 280°c,

Using substitution

T2= ((100*4.18*18) + (25*0.554*280))/ ((100*4.18) + (25*.554))

T2 = 26.4°c

So determine total entropy change

DStot = DSw + DSfe ...equat3

DStot = final entropy, DSw = entropy of water at T2, DSfe = final entropy of iron at T2 where,

DS = M.C. lin(T2/T1)...equ 5 temp is in Kelvin.

DSw = 100*4.18*lin(299.4/291) = 11.895

DSfe = 25*.554*lin(299.4/553) = -8.498.

Substituting answers into equa3

DStot = 11.895 - 8.498 = 3.397kj/kg*Kelvin

Explanation: the explanation is in the answers above..

3 0

3 years ago

What is the thermal efficiency of this reheat cycle in terms of enthalpies?

schepotkina [342]

Answer:

$\eta =\dfrac{\left (h_3-h_4\right )+(h_5-h_6)-(h_2-h_1)}{(h_3-h_2)+(h_5-h_4)}$

Explanation:

For close gas turbine:

Gas turbine works on Brayton cycle.Gas turbine have lots of applications like ,it is use in aircraft,in land applications etc.

Reheating is the method to improve the efficiency of the gas turbine.In reheating gas is expanding in two turbine instead of one turbine alone.Two turbine like high pressure turbine and low pressure turbine are used for expansion.

In the above diagram 1-2 is a compressor,2-3 heat addition,3-4 high pressure turbine,4-5 reheating of cycle 5-6 low pressure turbine,6-1 heat rejection,

We know that $\eta =\frac{W_{net}}{Q_{s}}$