Answer: Attached below is the missing diagram
answer :
A) 1) Wr > WI, 2) Qc' > Qc
B) 1) QH' > QH, 2) Qc' > Qc
Explanation:
л = w / QH = 1 - Qc / QH and QH = w + Qc
<u>A) each cycle receives same amount of energy by heat transfer</u>
<u>(</u> Given that ; Л1 = 1/3 ЛR )
<em>1) develops greater bet work </em>
WR develops greater work ( i.e. Wr > WI )
<em>2) discharges greater energy by heat transfer</em>
Qc' > Qc
solution attached below
<u>B) If Each cycle develops the same net work </u>
<em>1) Receives greater net energy by heat transfer from hot reservoir</em>
QH' > QH ( solution is attached below )
<em>2) discharges greater energy by heat transfer to the cold reservoir</em>
Qc' > Qc
solution attached below
Answer:
0.1 nm
Explanation:
Potential difference of the electron = 150 V
Mass of electron
Charge on electron
Plank's constant
If the velocity of the electron is v
Then according to energy conservation
According to De Broglie
Answer:
N = 278.5 rpm
F = 348.15 mm/min
machine time = 10.34 seconds
material removal rate = 33420000 mm³/min
Explanation:
given data
length L = 400 mm
width W = 60 mm
diameter D = 80 mm
no of cutting n = 5
velocity V = 70 m/min = 70000 mm/min
chip load P = 0.25 mm/tooth
depth = 5 mm
solution
we know velocity that is express as
velocity V = D N ........1
N =
N = 278.5 rpm
and
now we get feed rate in milling operation is
F n P N
F = 5 × 0.25 × 278.5
F = 348.15 mm/min
and
now we get actual machine time to make 1 pass across surface of worl is
machine time =
machine time =
machine time = 0.1723 min = 10.34 seconds
and
max material removal rate during these cut is
material removal rate = A × d × N
material removal rate = 400 × 60 × 5 × 278.5
material removal rate = 33420000 mm³/min