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ziro4ka [17]
3 years ago
8

Which explanation best identifies why the company in the following scenario has decided against investing in solar energy?

Engineering
1 answer:
pickupchik [31]3 years ago
8 0

Answer:

The company found the cost of the required photovoltaic cells too expensive.

Explanation:

Solar energy can be used as an alternative source of supply for fuel. Solar energy is a renewable source of energy, that is it keeps on replenishing every day. Also solar energy does not require a lot of maintenance.

The cost required is starting a solar system is very high because one needs to buy solar panel, photovoltaic cells for batteries, inverters and so on.

From the question, the company decided against solar energy for the time being. This means that probably in the future they might consider it. Therefore it is as a result of the economic situation of the company that they have not set up a solar system because the cost of the required photovoltaic cells too expensive.

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In alternating current, how often does the current alternate between negative and positive?
Novay_Z [31]

Answer:

AC voltages alternate/cycle, at a rate of 60 times each second.

7 0
2 years ago
Read 2 more answers
Two 2.30 cm × 2.30 cm plates that form a parallel-plate capacitor are charged to ± 0.708 nC . Part A What is the electric field
Alchen [17]

Answer:

A. E = 1.512\times 10^{5}\ V

B. 151.2 V

C. E = 1.512\times 10^{5}\ V

D. V = 302.4 V

Solution:

As per the question:

Area of the plates of the parallel plate capacitors, A = 2.30\times 2.30 = 5.29\ cm^{2} = 5.29\times 10^{- 4}\ m^{2}

Charge on the plates of the capacitor, Q_{c} = \pm 0.708\ nC = \pm 0.708\times 10^{- 9} \C

Now,

(A) To calculate the electric field strength, E when the separation distance, d = 1.00 mm = 10^{- 3}\ m:

E = \frac{Q}{\epsilon_{o}A}

E = \frac{0.708\times 10^{- 9}}{8.85\times 10^{- 12}\times 5.29\times 10^{- 4}} = 1.512\times 10^{5}\ N/C

(B) To calculate potential difference between the plates:

V = Ed = 1.512\times 10^{5}\times 10^{- 3} = 151.2V

(C) Electric field strength when spacing is 2 mm, i.e., 2\times 10^{- 3}\ m:

E = \frac{Q}{\epsilon_{o}A}

Since, the above expression of the electric field shows that it does not depend on the separation distance between the plates thus it will remain same, i.e., 1.512\times 10^{5}\ V

(D) Potential difference across the capacitor when d = 2\times 10^{- 3}\ m:

V = Ed = 1.512\times 10^{5}\times 2\times 10^{- 3} =302.4\ V

7 0
4 years ago
declare integer product declare integer number product = 0 do while product < 100 display ""Type your number"" input number p
Brilliant_brown [7]

Full Question

1. Correct the following code and

2. Convert the do while loop the following code to a while loop

declare integer product

declare integer number

product = 0

do while product < 100

display ""Type your number""

input number

product = number * 10

loop

display product

End While

Answer:

1. Code Correction

The errors in the code segment are:

a. The use of do while on line 4

You either use do or while product < 100

b. The use of double "" as open and end quotes for the string literal on line 5

c. The use of "loop" statement on line 7

The correction of the code segment is as follows:

declare integer product

declare integer number

product = 0

while product < 100

display "Type your number"

input number

product = number * 10

display product

End While

2. The same code segment using a do-while statement

declare integer product

declare integer number

product = 0

Do

display "Type your number"

input number

product = number * 10

display product

while product < 100

4 0
4 years ago
A wing component on an aircraft is fabricated from an aluminum alloy that has a plane strain fracture toughness of 27 . It has b
Mamont248 [21]

Answer:

The stress level at which fracture will occur for a critical internal crack length of 6.2mm is 135.78MPa

Explanation:

Given data;

Let,

critical stress required for initiating crack propagation Cc = 112MPa

plain strain fracture toughness = 27.0MPa

surface length of the crack = a

dimensionless parameter = Y.

Half length of the internal crack, a = length of surface crack/2 = 8.8/2 = 4.4mm = 4.4*10-³m

Also for 6.2mm length of surface crack;

Half length of the internal crack = length of surface crack/2 = 6.2/2 = 3.1mm = 3.1*10-³m

The dimensionless parameter

Cc = Kic/(Y*√pia*a)

Y = Kic/(Cc*√pia*a)

Y = 27/(112*√pia*4.4*10-³)

Y = 2.05

Now,

Cc = Kic/(Y*√pia*a)

Cc = 27/(2.05*√pia*3.1*10-³)

Cc = 135.78MPa

The stress level at which fracture will occur for a critical internal crack length of 6.2mm is 135.78MPa

For more understanding, I have provided an attachment to the solution.

4 0
4 years ago
Please read the short case at the end of Chapter 8, "Mary Barra of General Motors Values Culture". Use the following prompts to
Tom [10]

Answer: Incoherent question

Explanation: This is an act of plagiarism at subjecting the tutor to unnecessary stress at answering the purported question.

4 0
3 years ago
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