Find the solutions of the quadratic equation

Mathematics

1 answer:

Illusion [34]3 years ago

3 0

Answer:

x = $\frac{-3}{2} +- \frac{i*\sqrt{123}}{6}$

Step-by-step explanation:

x equals -b plus or minus square b squared minus 4 ac all over two a. Sing the song.

3x^2 + 9x + 17 = 0

a = 3

b = 9

c = 17

x = $\frac{-9 +- \sqrt{9^{2}-4*(3)*(17)}}{2*3}$

x = $\frac{-9 +- \sqrt{81-204}}{6}$

x = $\frac{-3}{2} +- \frac{\sqrt{-123}}{6}$

x = $\frac{-3}{2} +- \frac{i*\sqrt{123}}{6}$

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Points M, N, and P are respectively the midpoints of sides AC , BC , and AB of △ABC. Prove that the area of △MNP is on fourth of

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Answer:

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Step-by-step explanation:

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Median divides the area of a triangle in two equal parts.

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$\triangle ABC \sim \triangle NMP$