Answer:
Approximately 6.8m
Step-by-step explanation:
We can picture this problem by drawing a rectangular prism with a width of 5m, a depth of 3m, and a height of 3.5m. To find the length from one corner of the floor to the opposite corner of the floor, we can use the pythagorean theorem and plug in the width and depth of the room for a and b:

And now we can solve for c...


c = 5.831m
Now that we have the length from corner to corner across the floor, we can use the pythagorean theorem again, this time using the length from corner to corner across the floor we just derived and the height of the room:

And now we can solve for c again...

c = 6.8m
If you want to translate a point (x,y) to the left, you have to subtract the number of units (n) that you want to translate it from the original x coordinate, like this:
(x-u,y)
And if you want to translate a point (x,y) downwards, just subtract the number of units n you want to translate from the y coordinate, like this:
(x,y-n)
in this case, we have the point (-5,0) which image would be:
After a translation of 2 to the left
and with 1 unit down, this point would look like this:
(-5-2,0-1)=(-7,-1)
Answer:
you will need to know what's his gross monthly income and multiply by 25%that will give you the amount of taxes withheld and then subtract that from gross monthly income and that will give you Monthly take home pay.
Answer:
69.14% probability that the diameter of a selected bearing is greater than 84 millimeters
Step-by-step explanation:
According to the Question,
Given That, The diameters of ball bearings are distributed normally. The mean diameter is 87 millimeters and the standard deviation is 6 millimeters. Find the probability that the diameter of a selected bearing is greater than 84 millimeters.
- In a set with mean and standard deviation, the Z score of a measure X is given by Z = (X-μ)/σ
we have μ=87 , σ=6 & X=84
- Find the probability that the diameter of a selected bearing is greater than 84 millimeters
This is 1 subtracted by the p-value of Z when X = 84.
So, Z = (84-87)/6
Z = -3/6
Z = -0.5 has a p-value of 0.30854.
⇒1 - 0.30854 = 0.69146
- 0.69146 = 69.14% probability that the diameter of a selected bearing is greater than 84 millimeters.
Note- (The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X)