$4.25 for 64 fluid ounces

The maroon team and the orange team played a game of football. The maroon team scored 20 points and the orange team scored 6 poi

Dafna1 [17]

Answer:

20/6 or 10/3

Step-by-step explanation:

5 0

2 years ago

What is the solution of the inequality x^3+3x^2>7x+6

sveta [45]

Answer:

x>2

Step-by-step explanation:

x3+3x2=7x+6

x3+3x2−(7x+6)=7x+6−(7x+6)

x3+3x2−7x−6=0

(x−2)(x2+5x+3)=0

x−2=0 or x2+5x+3=0

x=2 or x=−0.6972243622680054 or x=−4.302775637731995

x<−4.302776

−4.302776<x<−0.697224

−0.697224<x<2

x>2(Works in original inequality)

3 0

2 years ago

A real estate agent has 19 properties that she shows. She feels that there is a 30% chance of selling any one property during a

netineya [11]

Answer:

$P(X \geq 5)=1-P(X$

We can find the individual probabilities:

$P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114$

$P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092$

$P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358$

$P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869$

$P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491$

And replacing we got:

$P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=19, p=0.3)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want to find this probability:

$P(X \geq 5)$

And we can use the complement rule:

$P(X \geq 5)=1-P(X$

We can find the individual probabilities:

$P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114$

$P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092$

$P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358$

$P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869$

$P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491$

And replacing we got:

$P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178$

4 0

3 years ago

H + 1/3 when h= 1 2/3

Bess [88]

2. Because if 1/3 + 2/3 is 1 then 1+1=2

8 0

3 years ago

Read 2 more answers

HELP PLEASE! PRE-ALGEBRA!

serious [3.7K]

Answer:

Triangle ABC is similar to triangle A prime B prime C prime., because Triangle A prime B prime C prime. is obtained by dilating Triangle ABC. by a scale factor of 1 over 2. and then rotating it about the origin by 180 degrees

Step-by-step explanation:

Step 1: Dilation by a scale factor of 1/2.

A point (x, y) is sent to (1/2 x, 1/2 y).

A(2, 2) ---> (1, 1)

B(2, 10) ---> (1, 5)

C(8, 12) ---> (4, 6)

Step 2: Rotate about the origin 180 degrees

A point (x, y) is sent to (-x, -y).

(1, 6) ---> A'(-1, -1)

(1, 5) ---> B'(-1, -5)

(4, 6) ---> C'(-4, -6)

6 0

3 years ago