Question

Which sine ratios are correct for ∆PQR? Check all that apply

Answer 1

Answer:

$sin(P)=\frac{p}{q}\\ sin(R)=\frac{r}{q}$

Step-by-step explanation:

In the given graph, we have the right triangle PQR, where q is the hypothenuse and r and p are legs.

Now, if we want to the sin function of an angle, it would be like

$sin(A)=\frac{opposite}{adjacent}$

That is, the sin of an angle is the quotient between its opposite leg and its adjacent leg.

So, in this case, if we apply this defintion to P and R angles, we have

$sin(P)=\frac{p}{q}\\ sin(R)=\frac{r}{q}$

Therefore, the right choices are the second and the last option.

$sin(P)=\frac{p}{q}\\ sin(R)=\frac{r}{q}$

Answer 2

Answer:

see explanation

Step-by-step explanation:

sinP = $\frac{opposite}{hypotenuse}$ = $\frac{QR}{PR}$ = $\frac{p}{q}$

sinR = $\frac{PQ}{PR}$ = $\frac{r}{q}$