Hi!
This question is about math.

<u><em>Least Common Factor 4 or 8: 8</em></u>
<u><em>Factors of 4 : 1, 2, 4 (prime factorization) (2*2)</em></u>
<u><em>Factors of 8: 1, 2, 4, 8 (prime factorization) (2*2*2)</em></u>
<u><em>Least Common Factor of a,b is the smallest positive number that divisible by both a and b.</em></u>
<em>Multiply each factor the greatest number of times it occurs in either 4 or 8.</em>
<em>Then multiply by the numbers.</em>


<em>Multiply each numerator by the same amount needed to multiply its corresponding denominator to turn it into the Least Common Factor of 8.</em>
<em>For 1/4 multiply the denominator and numerator by the 2.</em>


<em>Since the denominator are equal, combine the fractions.</em>

<em>Add the numbers 2+5=7</em>

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-Charlie
Start with 180.
<span>Is 180 divisible by 2? Yes, so write "2" as one of the prime factors, and then work with the quotient, 90. </span>
<span>Is 90 divisible by 2? Yes, so write "2" (again) as another prime factor, then work with the quotient, 45. </span>
<span>Is 45 divisible by 2? No, so try a bigger divisor. </span>
<span>Is 45 divisible by 3? Yes, so write "3" as a prime factor, then work with the quotient, 15 </span>
<span>Is 15 divisible by 3? [Note: no need to revert to "2", because we've already divided out all the 2's] Yes, so write "3" (again) as a prime factor, then work with the quotient, 5. </span>
<span>Is 5 divisible by 3? No, so try a bigger divisor. </span>
Is 5 divisible by 4? No, so try a bigger divisor (actually, we know it can't be divisible by 4 becase it's not divisible by 2)
<span>Is 5 divisible by 5? Yes, so write "5" as a prime factor, then work with the quotient, 1 </span>
<span>Once you end up with a quotient of "1" you're done. </span>
<span>In this case, you should have written down, "2 * 2 * 3 * 3 * 5"</span>
Answer:
Domain= how many boxes there are from each circle to the other, and the range is basically the height. In this case, Domain= 8, Range=2
Answer:
3
Step-by-step explanation:
The average rate of change is
f(x2) - f(x1)
-----------------
x2-x1
We want to find the change from 1 to 3
f(3) = 8
f(1) = 2
f(3) - f(1) 8-2 6
----------------- = ------------ = ---- = 3
3-1 2 2