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liubo4ka [24]
3 years ago
14

What is the solution set for - 4x + 10 > 5x + 55?

Mathematics
2 answers:
8_murik_8 [283]3 years ago
8 0

Answer:

d

Step-by-step explanation:

took the test

ivolga24 [154]3 years ago
5 0

Answer:

C

Step-by-step explanation:

‒4x‒5x>55‒10=‒9x>45

=‒9x/-9>45/‒9

=x<-5

i think it is easy &i hope my answer helps you

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exis [7]
The best answer is d
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3 years ago
Solve using the method of elimination and determine if the system has 1 solution, no solutions, or infinite solutions
Minchanka [31]

\begin{array}{rrrrr} 10x&-&18y&=&2\\ -5x&+&9y&=&-1 \end{array}~\hfill \implies ~\hfill \stackrel{\textit{second equation }\times 2}{ \begin{array}{rrrrr} 10x&-&18y&=&2\\ 2(-5x&+&9y&)=&2(-1) \end{array}} \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{rrrrr} 10x&-&18y&=&2\\ -10x&+&18y&=&-2\\\cline{1-5} 0&+&0&=&0 \end{array}\qquad \impliedby \textit{another way of saying \underline{infinite solutions}}

if we were to solve both equations for "y", we'd get

10x-18y=2\implies 10x-2=18y\implies \cfrac{10x-2}{18}=y\implies \cfrac{5}{9}x-\cfrac{1}{9}=y \\\\\\ -5x+9y=-1\implies 9y=5x-1\implies y=\cfrac{5x-1}{9}\implies y = \cfrac{5}{9}x-\cfrac{1}{9}

notice, the 1st equation is really the 2nd in disguise, since both lines are just pancaked on top of each other, every point in the lines is a solution or an intersection, and since both go to infinity, well, there you have it.

8 0
2 years ago
Someone help me out my grades are ba d
Natali5045456 [20]

Answer:

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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Complete the table for the radioactive iotope. (Round your anwer to 2 decimal place. Iotope : 239 Pu
Marizza181 [45]

If the radio active isotope has the half life of 24100 years, then the initial quantity is 2.16 grams

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Substitute the values in the equation

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Cancel the C in both side

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Here we have to apply ln to eliminate the e terms

ln (1/2) = 24100k

k = ln(1/2) / 24100

k = -2.87× 10^-5

To find the initial value we have to substitute the value of k and y in the equation

1.2 = Ce^{1000 ×  -2.87× 10^-5}

C = 1.2 / e^(-0.0287)

C = 2.16 gram

Hence, the initial quantity of the radioactive isotope is 2.16 gram

Learn more about half life here

brainly.com/question/4318844

#SPJ4

7 0
1 year ago
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Advocard [28]
The answer is 28.07. I just took this test
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3 years ago
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