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3 years ago

The population of a town increased from 3500 in 2006 to 5350 in 2011. Find the absolute and relative (percent) increase.

Mathematics

1 answer:

a_sh-v [17]3 years ago

7 0

Answer:

15% increase per year

Step-by-step explanation:

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190

TEA [102]

Answer:

Step-by-step explanation:

240000

5 0

2 years ago

Four lawn sprinkler heads are fed by a 1.9-cm-diameter pipe. The water comes out of the heads at an angle of 35° above the horiz

klemol [59]

Answer:

Step-by-step explanation:

Given:

Angle, θ = 35°

Vertical distance, Δx = 6 m

Diameter, d = 1.9 cm

= 0.019 m

When the water leaves the sprinkler, it does so at a projectile motion.

Therefore,

Using equation of motion,

(t × Vox) = 2Vo²(sin θ × cos θ)/g

= Δx = 2Vo²(sin 35 × cos 35)/g

Vo² = (6 × 9.8)/(2 × sin 35 × cos 35)

= 62.57

Vo = 7.91 m/s

Area of sprinkler, As = πD²/4

Diameter, D = 3 × 10^-3 m

As = π × (3 × 10^-3)²/4

= 7.069 × 10^-6 m²

V_ = volume rate of the sprinkler

= area, As × velocity, Vo

= (7.069 × 10^-6) × 7.91

= 5.59 × 10^-5 m³/s

Remember,

1 m³ = 1000 liters

= 5.59 × 10^-5 m³/s × 1000 liters/1 m³

= 5.59 × 10^-2 liters/s

= 0.0559 liters/s.

For the 4 sprinklers,

The rate at which volume is flowing in the 4 sprinklers = 4 × 0.0559

= 0.224 liters/s

Area of 1.9 cm pipe, Ap = πD²/4

= π × (0.019)²/4

= 2.84 × 10^-4 m²

Volumetric flowrate of the four sprinklers = 4 × 5.59 × 10^-5 m³/s

= 2.24 × 10^-4 m³/s

Velocity of the water, Vw = volumetric flowrate/area

= 2.24 × 10^-4/2.84 × 10^-4

= 0.787 m/s

7 0

2 years ago

Read 2 more answers

The monthly amounts spent for food by families of four receiving food stamps approximates a symmetrical, normal distribution. Th

e-lub [12.9K]

Answer:

95% of monthly food expenditures are between $110 and $190.

Step-by-step explanation:

Given : The monthly amounts spent for food by families of four receiving food stamps approximates a symmetrical, normal distribution. The sample mean is $150 and the standard deviation is $20.

To find : Using the Empirical rule, about 95% of the monthly food expenditures are between which of the following two amounts?

Solution :

At 95% of the data is between two standard deviation to left and right of the mean is given by,

To the left side, $\bar{x}-2\sigma$

To the right side, $\bar{x}+2\sigma$

We have given,

The sample mean $\bar{x}=\$150$

The standard deviation $\sigma=\$20$

Substitute in the formula,

$\bar{x}-2\sigma$

$=150-2(20)$

$=150-40$

$=110$

$\bar{x}+2\sigma$

$=150+2(20)$

$=150+40$

$=190$

Therefore, 95% of monthly food expenditures are between $110 and $190.

6 0

2 years ago

What expression are equivalent 4^-32/4^2?

pickupchik [31]

4^32=22.627417 and 4^2=16

5 0

2 years ago

Katie has 50 chickens she eats 90% how many chickens are left?

Dmitry [639]

45
Find ten percent of 50 by moving the decimal point left once and subtract it from 50

5 0

2 years ago

Read 2 more answers