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Alex787 [66]
3 years ago
15

The area of polygon MNOPQR = Area of a rectangle that is 9 square units + Area of a rectangle that is ___ square units. (Input w

hole numbers only, such as 8.)
Mathematics
1 answer:
vekshin13 years ago
8 0
You have the polygon MNOPQR which can be expressed as two rectangles pasted one next to each other.

To see the two rectangles in the picture, you can draw a line parallel to segment MR througn point N.

From the original picture you can state the dimensions of both rectangles.

Call S, the point where the line that you drew intercepts the segment RQ.

Then one rectangle is MNSR and the other rectangle is OPQS.

The measures of the sides of the rectangle MNSR are:

- the length of MN = length of SR = base

- the length of MR = the length of NS.= height

So its area is base * height, which you can all A1.

The measured of the rectangle OPQS are:

- segment OP = segment SQ = segment QR - segment SR = base

- segment PQ = segment OS = height

So its area is base * height, which you can call A2.

Then the area of the polygon MNOPQRS is A1 + A2. One of them is 9 u^2 and the other is what the answer is asking for, and that you have calculated above.

With this procedure you can tell the value needed.   

 
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Complete question :

Mr. Nelson lost one of his students' test papers. He knows that the other 4 students scored as follows: 60, 62, 56, 57. He also knows that the average score is 59.2. What is the score on the missing paper?

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Step-by-step explanation:

Given the following :

Total number of students = 4 + 1 missing = 5

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Average score of the 5 papers = 59.2

Score on missing paper :

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Let missing score = m

(60 + 62 + 56 + 57 + m) = 235 + m

Recall:

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Hence,

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