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liraira [26]
2 years ago
11

Please help ill give brainliest

Mathematics
2 answers:
garri49 [273]2 years ago
7 0
Something like 44+22x=77
defon2 years ago
6 0

Answer:

1.50$

Step-by-step explanation:

You might be interested in
Please give me the answer please
In-s [12.5K]
If there are 4 trucks then the first truck weighs x
then x+2tons
then x+4tons
then x+6tons = 32tons
so 4x+12=32
         -12   -12
     /4         /4
x=5 
so plug it back in 
truck 1= 5tons or 10,000lbs
truck 2= 7tons or 14,000lbs
truck 3= 9tons or 18,000lbs
truck 4= 11tons or 22,000lbs

5 0
2 years ago
Can someone please help me
Rzqust [24]

Answer:

the graph of the function is non-linear

the table can be represented by the equation y=4x+4

Step-by-step explanation:

non linear because 1+7=8 and then 10+2 = 12 so they have different numbers to add each time

represented by the equation because the x numbers (1,2,3,4,) all multiplied by 4 and added by 4 gives you y

any more help just ask :)

3 0
2 years ago
The graph for the equation y=-2x+1 is shown below. If another equation is graphed so that the system has no solution, which equa
12345 [234]
Y=-2x+3 (could be any y-int as long as it has the same slope)

This line is parallel to the original line so they never intersect

Therefore the answer is no solution
5 0
3 years ago
The temperature of a freezer started at 18ºC. After cooling for a few hours, the freezer had a temperature of –12ºC. What is the
Zarrin [17]

Answer:

a.–12 – 18

Step-by-step explanation:

We have to compute the difference (the subtraction) between the new, colder temperature, which is equal to -12 °C, and the original temperature, which is equal to 18 °C, that is:

colder temperature - original temperature

Replacing with data:

-12 °C - 18 °C = -30 °C

5 0
3 years ago
Read 2 more answers
Jason went to the post office and bought both 41-cent stamps and 26-cent postcards and spent $10.28. The number of stamps was 4
Charra [1.4K]
<h3>Jason bought 20 stamps of $0.41 each and 8 postcards of $0.26 each.</h3>

<em><u>Solution:</u></em>

Let stamps be s and postcards be p

Given that,

The number of stamps was 4 more than twice the number of postcards

s = 4 + 2p -------- eqn 1

Jason bought both 41-cent stamps and 26-cent postcards and spent $10.28

41 cent = $ 0.41

26 cent = $ 0.26

Therefore,

s \times 0.41 + p \times 0.26 = 10.28

0.41s + 0.26p = 10.28 --------- eqn 2

Substitute eqn 1 in eqn 2

0.41(4 + 2p) + 0.26p = 10.28

1.64 + 0.82p + 0.26p = 10.28

1.08p = 10.28 - 1.64

1.08p = 8.64

Divide both sides by 1.08

p = 8

Substitute p = 8 in eqn 1

s = 4 + 2(8)

s = 4 + 16

s = 20

Thus Jason bought 20 stamps and 8 post cards

8 0
3 years ago
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