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sergij07 [2.7K]
3 years ago
13

HELP ASAP DUE TODAY PLZ HELP Solve the equation for x. 17=5+23x

Mathematics
1 answer:
LenKa [72]3 years ago
5 0

Answer:

x=12/23

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

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Calculate the length of ac
svlad2 [7]

Answer:

  12.1 cm

Step-by-step explanation:

Using the law of sines, we can find angle C. Then from the sum of angles, we can find angle B. The law of sines again will tell us the length AC.

  sin(C)/c = sin(A)/a

  C = arcsin((c/a)sin(A)) = arcsin(8.2/13.5·sin(81°)) ≈ 36.86°

Then angle B is ...

  B = 180° -A -C = 180° -81° -36.86° = 62.14°

and side b is ...

  b/sin(B) = a/sin(A)

  b = a·sin(B)/sin(A) = 13.5·sin(62.14°)/sin(81°) ≈ 12.0835

The length of AC is about 12.1 cm.

_____

<em>Comment on the solution</em>

The problem can also be solved using the law of cosines. The equation is ...

  13.5² = 8.2² +b² -2·8.2·b·cos(81°)

This is a quadratic in b. Its solution can be found using the quadratic formula or by completing the square.

  b = 8.2·cos(81°) +√(13.5² -8.2² +(8.2·cos(81°))²)

  b = 8.2·cos(81°) +√(13.5² -(8.2·sin(81°))²) . . . . . simplified a bit

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Johnny walks 3600 feet in 9 minutes. How many miles does he walk per minute?
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Answer:

0.075758 miles per minute

Step-by-step explanation:

3600 divided by 9 = 400

400 ft = 0.075758 miles

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Step-by-step explanation:

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Help me with question a please ! With full workings !
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A)


\bf \textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;Q&({{ 0}}\quad ,&{{ 2}})\quad &#10;%  (c,d)&#10;P&({{ 0.5}}\quad ,&{{ 0}})&#10;\end{array}\qquad &#10;%  distance value&#10;d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}

\bf QP=\sqrt{(0.5-0)^2+(0-2)^2}\implies QP=\sqrt{0.5^2+2^2}&#10;\\\\\\&#10;QP=\sqrt{\left( \frac{1}{2} \right)^2+4}\implies QP=\sqrt{ \frac{1^2}{2^2}+4}\implies QP=\sqrt{\frac{1}{4}+4}&#10;\\\\\\&#10;QP=\sqrt{\frac{17}{4}}\implies QP=\cfrac{\sqrt{17}}{\sqrt{4}}\implies QP=\cfrac{\sqrt{17}}{2}

b)

since QR=QP, that means that QO is an angle bisector, and thus the segments it makes at the bottom of RO and OP, are also equal, thus RO=OP

thus, since the point P is 0.5 units away from the 0, point R is also 0.5 units away from 0 as well, however, is on the negative side, thus R (-0.5, 0)


c)

what's the equation of a line that passes through the points (-0.5, 0) and (0,2)?

\bf \begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%   (a,b)&#10;Q&({{ 0}}\quad ,&{{ 2}})\quad &#10;%   (c,d)&#10;R&({{ -0.5}}\quad ,&{{ 0}})&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope = {{ m}}= \cfrac{rise}{run} \implies &#10;\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{0-2}{-0.5-0}\implies \cfrac{-2}{-0.5}

\bf m=\cfrac{\frac{-2}{1}}{-\frac{1}{2}}\implies \cfrac{-2}{1}\cdot \cfrac{2}{-1}\implies 4&#10;\\\\\\&#10;% point-slope intercept&#10;y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-2=4(x-0)\implies y=4x+2\\&#10;\left. \qquad   \right. \uparrow\\&#10;\textit{point-slope form}
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