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svetlana [45]
3 years ago
14

I NEED HELP I'M IN TIMER:

Mathematics
2 answers:
alekssr [168]3 years ago
8 0

1/2x - 7 = 1 5/10

I'd go with c.

Katarina [22]3 years ago
5 0

Answer:

The answer is C.x/2-7=1.5

Step-by-step explanation:

Im 100% positive!!!!!!!!!!!!!!!!!

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PLS HELP!! ASAPPPPPPPP
morpeh [17]
Keep the denominator
5 0
2 years ago
PLEASE PLEASE I SUCK AT MATH AND ITS ALL DUE FRIDAY PLEASE 10 piont !!! Select all the correct systems of equations.
alekssr [168]

Answer:

2x + y = 17

-6x = 3y - 51

Step-by-step explanation:

You get an infinite number of solutions when two equations are really just the same. This means you can convert one into the other simply by multiplying one to get the other.

In the above answer, if you multiply the above by -3 you get:

-6x -3y = -51

which is of course -6x = 3y - 51

So that is an example of a pair that has infinite solutions.

To find all of them, you'd carefully have to compare each 2 and see if there is a multiplier to convert one into the other. You can do that!

4 0
2 years ago
The cost of 2 kg of onions is ₹24. What will the cost of 12 kg of onions be?​
max2010maxim [7]

Answer:

144 rupees

Step-by-step explanation:

2 kg= 24 rupees

2/2 kg= 24/2 rupees

1 kg= 12 rupees

1×12 kg= 12×12 rupees

12 kg= 144 rupees

8 0
2 years ago
The product of two fractions that are each between 0 and 1 is also between 0 and 1.Is this true or false?
Ksenya-84 [330]
True 

merry Christmas and a happy new year :)
7 0
2 years ago
Read 2 more answers
Find the value of kk for which the constant function x(t)=kx(t)=k is a solution of the differential equation 5t3dxdt+2x−2=05t3dx
uranmaximum [27]
Given the differential equation

5t^3 \frac{dx}{dt} +2x-2=0

The solution is as follows:

5t^3 \frac{dx}{dt} +2x-2=0 \\  \\ \Rightarrow5t^3 \frac{dx}{dt} =2-2x \\  \\ \Rightarrow \frac{5}{2-2x} dx= \frac{1}{t^3} dt \\  \\ \Rightarrow \int {\frac{5}{2-2x} } \, dx = \int {\frac{1}{t^3}} \, dt \\  \\ \Rightarrow- \frac{5}{2} \ln(2-2x)=- \frac{1}{2t^2} +A \\  \\ \Rightarrow\ln(2-2x)= \frac{1}{5t^2} +B\\  \\ \Rightarrow2-2x=Ce^{\frac{1}{5t^2}} \\  \\ \Rightarrow 2x=Ce^{\frac{1}{5t^2}}+2 \\  \\ \Rightarrow x=De^{\frac{1}{5t^2}}+1
3 0
2 years ago
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