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Alchen [17]
2 years ago
10

139 students choose to attend one of three after school activities: football, tennis or running.

Mathematics
1 answer:
attashe74 [19]2 years ago
5 0
Answer: 29/139

Explanation:

Total student: 139 (66 boys/73 girls)

Football: 56 student (28 boy/28 girl)

Tennis: 54 student (27 boy/ 27 girl)

Running: 29 student (18 girls/11 boys)

The probability that a student chose running is 29/139

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damaskus [11]
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7 0
3 years ago
To convert a distance of 12000 feet to miles which ratio could you multiply by?
Luba_88 [7]

Answer:

2.28 miles

Step-by-step explanation:

1 foot = 0.00019miles

12000 feet = x miles

Cross multiply

x = 12000 x 0.00019

x = 2.28 miles

5 0
3 years ago
What do u add to 3 and 3 / 8 to make 7
Gnom [1K]

Answer:

3 \frac{5}{8}

Step-by-step explanation:

A simple question, but I decided to answer.

Good Luck!!

8 0
3 years ago
Read 2 more answers
The diameters of ball bearings are distributed normally. The mean diameter is 87 millimeters and the standard deviation is 6 mil
devlian [24]

Answer:

69.14% probability that the diameter of a selected bearing is greater than 84 millimeters

Step-by-step explanation:

According to the Question,

Given That, The diameters of ball bearings are distributed normally. The mean diameter is 87 millimeters and the standard deviation is 6 millimeters. Find the probability that the diameter of a selected bearing is greater than 84 millimeters.

  • In a set with mean and standard deviation, the Z score of a measure X is given by Z = (X-μ)/σ

we have μ=87 , σ=6 & X=84

  • Find the probability that the diameter of a selected bearing is greater than 84 millimeters

This is 1 subtracted by the p-value of Z when X = 84.

So, Z = (84-87)/6

Z = -3/6

Z = -0.5 has a p-value of 0.30854.

⇒1 - 0.30854 = 0.69146

  • 0.69146 = 69.14% probability that the diameter of a selected bearing is greater than 84 millimeters.

Note- (The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X)

7 0
3 years ago
There are 20,000 members of a zoo. The percent of
schepotkina [342]

1500 members have a contributor  membership.

64.8% of the noncontributory  memberships are individual memberships.

<u>Step-by-step explanation:</u>

There are 20,000 members of a zoo.

⇒ Total members = 20,000

From the graph shown,

7.5% of the members have a contributor  membership.

<u>To find the number of members who have contributor  membership :</u>

⇒ 7.5% of 20,000

⇒ (7.5/100) × 20,000

⇒ 7.5 × 200

⇒ 1500 members.

Therefore, 1500 members have a contributor  membership.

<u>To find the percentage of the noncontributory  memberships are individual memberships :</u>

The percentage of noncontributory  memberships = 100% - 7.5% ⇒ 92.5%

The percentage of individual memberships = 60%

∴ What percentage of the noncontributory  memberships are individual memberships ⇒ (60 / 92.5) × 100 = 64.8%

3 0
3 years ago
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