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3 years ago

A line has a slope of zero and passes through the point (-2, 3). Which of the following points must also lie on the line?

Mathematics

2 answers:

ikadub [295]3 years ago

7 0

Answer:

Your answer will be (-2,5)

KatRina [158]3 years ago

4 0

Any point with an x coordinate that is -2.

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The variance of a distribution is 195. What is the standard deviation, rounded to the nearest thousandth?

stiks02 [169]

Given:

The variance of a distribution = 195.

To find:

The standard deviation, rounded to the nearest thousandth.

Solution:

Standard deviation of a distribution is the square root of the variance of the distribution.

Here, the standard deviation of the distribution is

$S.D.=\sqrt{195}$

$S.D.=13.96424$

$S.D.\approx 13.964$

Therefore, the standard deviation is 13.964.

8 0

3 years ago

What linear equation is represented by the table? 1

rewona [7]

Answer:

Y=4x-2

Step-by-step explanation:

You have to try it (x,y) (2,6)

y=4x-2

6=4(2)-2

6=8-2

8 0

2 years ago

Given m||n, find the value of x.<br><br> (7%-10)<br> (6X-5)

tamaranim1 [39]

15 degrees

7x-10+6x-5=180

13x=180

x=15

6 0

2 years ago

Part A: Larry earned $11 walking his neighbors' dogs on Saturday. He earned some extra money on Sunday doing the same thing. Wri

djyliett [7]

So for part a the answer with be 11/6
Why 6 because count the weeks that wil be 6 so Monday Tuesday Wednesday thursaday and Friday then comes Saturday

3 0

2 years ago

Read 2 more answers

18. Determine the common difference, the fifth term, and the sum of the first 100 terms of the following sequence:

Ksenya-84 [330]

$a_1=1,\ a_2=2.5,\ a_3=4,\ a_4=5.5,\ ...\\\\a_2-a_1=2.5-1=1.5\\a_3-a_2=4-2.5=1.5\\a_4-a_3=5.5-4=1.5\\a_{n+1}-a_n=1.5=constans\\\\\text{It's an arithmetic sequence with}\\a_1=1,\ \boxed{d=1.5}\\\\a_n=a_1+(n-1)d\to a_n=1+(n-1)(1.5)=1+1.5n-1.5\\\\a_n=1.5n-0.5\\\\a_5=1.5(5)-0.5=7.5-0.5=7\\\boxed{a_5=7}\\\\\text{The formula of a Sum of the First n Terms of an Arithmetric Sequence:}\\\\S_n=\dfrac{2a_1+(n-1)d}{2}\cdot n\\\\\text{We have:}\\a_1=1,\ d=1.5,\ n=100\\\\\text{Substitute}$

$S_{100}=\dfrac{(2)(1)+(100-1)(1.5)}{2}\cdot100=\dfrac{2+(99)(1.5)}{1}\cdot50\\\\=(2+148.5)\cdot50=150.5\cdot50=7,525\\\\\boxed{S_{100}=7,525}\\\\Answer:\\the\ common\ difference:\ d=1.5\\the\ fifth\ term:\ a_5=7\\the\ sum\ of\ first\ 100\ terms:\ S_{100}=7,525$

8 0

3 years ago