So the equation of a circle is (x - h)² + (y - k)² = r² where (h,k) are the coordinates of the center of the circle and r is the radius. The diameter of a circle is a line that goes from one point of the circle to the other through the center of the circle. Well the center would be midway through the diameter so use midpoint formula to find the center which is (h,k) Mid point formula is both given x's added together divided by 2 for h and both y coordinates added together divided by 2 to find k
(10+0)/2
10/2= 5
(12+2)/2
14/2 = 7
so the center of the circle is (5,7) now use distance formula using the center and one of the points to the radius
√((5-10)²+(7-12)²)
√(-5²+ -5²)
√(25 + 25)
√50 is the radius
Now plug all found information into circle equation
(x-5)² + (y-7)² =50 note the end is 50 because the circle equation is radius squared and since the radius is √50, radius² is 50.
Answer is c
9514 1404 393
Answer:
7 square units
Step-by-step explanation:
There are several ways the area of triangle EBD can be found.
- find the lengths EB, BD, DE and use Heron's formula (messy due to roots of roots being involved).
- define point G at the lower left corner and subtract the areas of ∆DEG and BCD from trapezoid BCGE.
- figure the area from the coordinates of the vertices.
- use Pick's theorem and count the dots.
We choose the latter.
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Pick's theorem says the area of a polygon can be found as ...
A = i + b/2 -1
where i is the number of grid intersection points interior to the polygon, b is the number of grid points intersected by the border.
The attached figure shows the lines EB, BD, and DE intersect one point in addition to the vertices. So, b=4. A count of the red dots reveals 6 interior points (i=6). So, the area is ...
A = 6 + (4/2) -1 = 7
The area of ∆EBD is 7 square units.
The <span>initial value is 65 since that is the y intersept.</span>
Equation = a² + b² = c²
a = 80
b = 39
c = Diagonal
a² + b² = c²
80² + 39² = c²
6400 + 1521 = c²
c² = 7921
c = √7921
c = 89
Answer = 89 units
Answer:
x+y+2=-5 -2x-y+2=-1 x-2y-2=0 solve algebraically
x+y+2=-5 equation 1
-2x-y+2=-1 equation 2
x-2y-2=0 equation 3
Add equation 1 + 2+ 3
x+y+2=-5 + -2x-y+2+1 + x-2y-2
x+y+2= -7+2+1-2x+x+y
x+y+2= -4-x+y
x+y+2+4+x-y= 0
2x+6= 0
2x= -6
divide both side by 2
x= -3
from equation 1 insert x
x+y+2=-5
since x=-3
then, -3+2+y= -5
-1+y= -5
y= -5+1
y= -4
Step-by-step explanation:
