Question

Use the Law of Logarithm to expand the expression. ln(y √x/z (I know the answer is 2ln(y)+ln(x)-ln(z) all over 2, but I need the steps to get there)

Answer 1

Answer:

$in (y\sqrt{\frac{x}{y}}) =\frac{1}{2} in(x)-\frac{1}{2} in(z) +in(y)$

Step-by-step explanation:

From the question we are told that the expression $ln(y √x/z$

$in (y\sqrt{\frac{x}{y}})$

$in(y)+in(y\sqrt{\frac{x}{y}})$

$in(xy)=in(x)+in(y)$

$in(xy)=in\frac{x}{z} ^1^/^2 +in(y)$

$in(xy)=\frac{1}{2} in(\frac{x}{z}) +in(y)$

$in(xy)=\frac{1}{2} in(x)-in(z) +in(y)$

$in(xy)=\frac{1}{2} in(x)-\frac{1}{2} in(z) +in(y)$

Mathematically

$in (y\sqrt{\frac{x}{y}}) =\frac{1}{2} in(x)-\frac{1}{2} in(z) +in(y)$