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Vanyuwa [196]
3 years ago
9

Twice the larger of two consecutive integers is equal to fifteen less than three times the smaller. Find the integers.

Mathematics
1 answer:
Alexxandr [17]3 years ago
7 0

Answer:

17,18

Step-by-step explanation:

let the smaller integer be "a" and the larger be "b"

Then 2b = 3a -15              ........................equ 1

but they are consecutive integers, b= a+1 ; substitute b into equ 1,thus,

2(a+1) = 3a - 15

2a + 2 = 3a-15

collect like terms,

2+15 =3a-2a

17 = a

b= a+1

b = 17+1

b=18.

The integers are 17,18

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<u>Corrected question :</u>

Solve the equation. Write your answer as an integer or simplified fraction.

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<u>Required Solution :</u>

The given equation,

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★ Multiplying -7 into (n - 2),

>> 8n - 7 × (n - 2) = 18

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>> n = 14

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