All categories

4 years ago

X+y=26 3x+8y=123 What is x equal

Mathematics

1 answer:

Pani-rosa [81]4 years ago

5 0

Answer:

x=17, y=9. (17, 9).

Step-by-step explanation:

x+y=26

3x+8y=123

------------------

x=26-y

3(26-y)+8y=123

78-3y+8y=123

78+5y=123

5y=123-78

5y=45

y=45/5

y=9

x=26-9=17

You might be interested in

Find the area of a segment formed by a chord 8" long in a circle with radius of 8"

AlekseyPX

$r=8\\\\P=\pi r^2\\\\P=\pi\cdot8^2=64\pi$

5 0

3 years ago

20 POINTS!! ASAP, PLS SHOW WORK TYY

Sergeeva-Olga [200]

Answer:

$\sin(\theta)=-\sqrt5/5\text{ and } \csc(\theta)=-\sqrt5\\\cos(\theta)=2\sqrt5/5\text{ and } \sec(\theta)=\sqrt5/2\\\tan(\theta)=-1/2\text{ and } \cot(\theta)=-2$

Step-by-step explanation:

First, let's determine which quadrant our angle θ lies in.

Remember ASTC, where:

Everything is positive in QI,

Only sine (and cosecant) is positive in QII,

Only tangent (and cotangent) is positive in QIII,

And only cosine (and secant) is positive in QIV.

Since our tangent is negative, and our cosine is positive, this means that our θ must be in QIV.

In QIV, sine is negative, tangent is negative, and cosine is positive.

With that, let's figure out the remaining trig ratios.

We know that:

$\tan(\theta)=-1/2$

Remember that tangent is the ratio of the opposite side to the adjacent side.

Let's figure out our hypotenuse using the Pythagorean Theorem:

$a^2+b^2=c^2$

Substitute 1 for a and 2 for b (we can ignore the negative since we're squaring anyways). This yields:

$(1)^2+(2)^2=c^2$

Square:

$1+4=c^2$

Add:

$c^2=5$

Take the square root:

$c=\sqrt{5}$

So, our square root is √5.

So, our three sides are: Opposite=1, Adjacent=2, and Hypotenuse=√5.

Sine and Cosecant:

Remember that:

$\sin(\theta)=opp/hyp$

Substitute 1 for the opposite and √5 for the hypotenuse. This yields:

$\sin(\theta)=1/\sqrt5$

Rationalize:

$\sin(\theta)=\sqrt5/5$

And since our angle is in QIV, we add a negative:

$\sin(\theta)=-\sqrt5/5$

Cosecant is simply the reciprocal of sine. So:

$\csc(\theta)=-\sqrt5$

Cosine and Secant:

Remember that:

$\cos(\theta)=adj/hyp$

Substitute 2 for the adjacent and √5 for the hypotenuse. This yields:

$\cos(\theta)=2/\sqrt5$

Rationalize:

$\cos(\theta)=2\sqrt5/5$

Since our angle is in QIV, cosine stays positive.

Secant is the reciprocal of cosine. So:

$\sec(\theta)=\sqrt5/2$

Tangent and Cotangent:

We were given that:

$\tan(\theta)=-1/2$

To find cotangent, flip:

$\cot(\theta)=-2$

And we're done!

7 0

3 years ago

Given that h(x)=x³-2, evaluate h(4) pls help me!

ahrayia [7]

Hello and Good Morning/Afternoon:

Let's take this problem step-by-step:

The problem want's to find h(4)

$\hookrightarrow \text{4 in this case is the x's value}\\$

$\hookrightarrow\text{This means that we must plug in x into x's position in h(x)'s equation}$

$h(4) = (4)^3-2=64-2=62$

Answer: h(4) = 62

Hope that helps!

#LearnwithBrainly

6 0

2 years ago

Jarrett's puppy weighted 3 3 3/4 ounce at birth.at 1 week old he weighted 5 1/8 ounces.if his weight gain countiues in the patte

Arte-miy333 [17]

First in order to find the pattern, you need to find the number of pounds that the puppy gained from birth to a week after birth.
5 1/8 - 3 3/4=5 1/8 - 3 6/8=4 9/8 - 3 6/8=1 3/8 pounds gained
(1 3/8)(3)=(11/8)(3/1)=33/8=4 1/8 pounds gained
4 1/8 + 3 3/4=4 1/8 + 3 6/8=7 7/8 pounds at week 3

8 0

3 years ago

Please help me please I feel like crying cause I can't do it...

Mila [183]

Answer:

1. 39

2. 15

3.329

4. 16

5. 300

Step-by-step explanation:

Just divide the first two numbers and then multiply the quotient by the last number. You'll be ok, you've got this, keep your head up!

1. 52/4 = 13 and 13 x 3 = 39

2. 45/9 = 5 and 5 x 3 = 15

3. 470/10 = 47 and 47 x 7 = 329

4. 10/2.5 = 4 and 4 x 4 = 16

5. 125/2.5 = 50 and 50 x 6 = 300

4 0

3 years ago