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kkurt [141]
1 year ago
13

Given that h(x)=x³-2, evaluate h(4) pls help me!

Mathematics
1 answer:
ahrayia [7]1 year ago
6 0

Hello and Good Morning/Afternoon:

<u>Let's take this problem step-by-step</u>:

<u>The problem want's to find h(4)</u>

  \hookrightarrow \text{4 in this case is the x's value}\\

       \hookrightarrow\text{This means that we must plug in x into x's position in h(x)'s equation}

                  h(4) = (4)^3-2=64-2=62

<u>Answer: h(4) = 62</u>

<u></u>

Hope that helps!

#LearnwithBrainly

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There are 12 squares and 4 triangles. What is the equation that compares the number of squares s to the number of triangles t?
anastassius [24]
12subtract4
12-4
they want me to write more then 20 charaters

4 0
4 years ago
4.
denis23 [38]
The answer is none. There are no solutions
6 0
3 years ago
En la preparación de un perfume se cuenta con dos tipos de esencia base: 1600 ml de una y 1680 ml de otra. Se quiere envasarlas,
Lostsunrise [7]

Answer:

33,600 frascos

Step-by-step explanation:

Resolvemos esta pregunta utilizando el método mínimo común múltiple

Encuentre y enumere los múltiplos de 1600 y 1680 hasta encontrar el primer múltiplo común. Este es el mínimo común múltiplo.

Múltiplos de 1600:

1600, 3200, 4800, 6400, 8000, 9600, 11200, 12800, 14400, 16000, 17600, 19200, 20800, 22400, 24000, 25600, 27200, 28800, 30400, 32000, 33600, 35200, 36800

Múltiplos de 1680:

1680, 3360, 5040, 6720, 8400, 10080, 11760, 13440, 15120, 16800, 18480, 20160, 21840, 23520, 25200, 26880, 28560, 30240, 31920, 33600, 35280, 36960

Por lo tanto,

LCM (1600, 1680) = 33,600

La menor cantidad de frascos necesarios es 33,600 frascos.

4 0
3 years ago
What function does 3x+7=y represent
Arisa [49]

Answer:

line

Step-by-step explanation:

that is a line in the form y = mx + b

slope = m = 3

y intercept = b = 7

3 0
3 years ago
An arithmetic sequence has a1 = 22 and a8 = 43. Find a15.
brilliants [131]

The 15th term of the arithmetic sequence a_{15} = 64

Option B is correct

The nth term of an arithmetic sequence is given as:

a_{n} = a + (n - 1)d

The first value, a = 22

a_8 = a+(8 - 1)d\\a_8 = a + 7d

Since a_8 = 43

43 = 22 + 7d\\7d = 43 - 22\\7d = 21\\d = \frac{21}{7}\\d = 3

The common difference, d = 3

a_{15}= a + (15-1)d\\a_{15} = a + 14d\\a_{15} = 22 + 14(3)\\a_{15} = 22 + 42\\a_{15} = 64

The 15th term of the arithmetic sequence = 64

Learn more here: brainly.com/question/24072079

4 0
2 years ago
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