Yes it will isnt that amazing now you can do more stuff.
Complete question is;
How many 10 - digit numbers are there, such that the sum of the digits is divisible by 2?
Answer:
There are 4500000000 ten digit numbers whose sum is divisible by 2.
Step-by-step explanation:
Since we are dealing with 10 digit numbers, the first 10 digit number whose sum is divisible by 2 is; 1000000001.
While the last 10 digit number whose sum is divisible by 2 is 9999999999.
Now,to find how many 10 digit numbers whose sum are divisible by 2, we will simply divide the difference of both numbers by 2 and then add 1 to the answer. This is because subtracting the minimum from the maximum gives us the number of 10 digit numbers we have. Then dividing by 2 gives the number of ten digit numbers with sum divisible by 2 in between. Then adding 1 to the result to cover the number not included gives;
((9999999999 - 1000000001)/2) + 1 = 4500000000
Answer:1.21x
Step-by-step explanation:
Let the initial population was x
(1.1x)*1.1=1.21x
Answer:
The answer is D
Step-by-step explanation:
I tested this in apex learning and got 100 so its true.
Answer:
226.08
Step-by-step explanation:
Atop = (3.14)(4)²
= 50.24
Abottom = Atop = 50.24
Aside = C x H
C = 2πr
= 2(3.14)(4)
= 25.12
25.12 * 5
= 125.6
125.6 + 50.24 + 50.24
= 226.08