Question

What are the solutions for x to the equation (x-3)(x+8)=0

Answer 1

For this case we have a factored expression, of a second degree equation:

($(x-3) (x + 8) = 0$

To find the solutions:

• $x-3 = 0$

we add 3 to both sides of the equation:

$x=3$

• $x+8=0$

We subtract 8 on both sides of the equation:

$x = -8$

Thus, the solutions of the equation are:

$x_ {1} = 3\\x_ {2} = - 8$

Answer:

$x_ {1} = 3\\x_ {2} = - 8$