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2 years ago

Hannah buys 2/3 pound of roast beef. She uses 1/4 pound to make sandwiches for lunch. How much roast beef does she have left?

2 answers:

7 0

First we need to make both fractions equal to each other, and that means having to have the denominators the same.

What both 3 and 12 easily go into is 12.

So we need to make both fractions have a denominator of 12, so we multiply.

2/3 * 4/4 = 8 / 12

1/4 * 3/3 = 3 / 12

Now, we know that she has 8 / 12 pounds, and she uses 3 / 12 of it, so now we subtract to find how much she has left.

8 - 3 = 5

Out of the 12 pounds of roast beef, she now has 5 / 12 left.

EastWind [94]2 years ago

3 0

Well you have to find the common denominator. You have to look for the common multiples. When you find it (12) you have to multuply the numerator the same you multipied the denominator. So it's 8/12-3/12. 8-3=5 and the denominstor stays the same.

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A cylinder has a base diameter of 16 feet and a height of 19 feet. What is its volume in cubic feet, to the nearest tenths place

Tresset [83]

Answer: Volume = 3818.2 cubic feet

Step-by-step explanation:

The formula for determining the volume of a cylinder is expressed as

Volume = πr²h

Where

r represents the radius of the cylinder.

h represents the height of the cylinder.

π is a constant whose value is 3.14

From the information given,

Diameter = 16 feet

Radius = diameter/2 = 16/2

Radius = 8 feet

Height = 19 feet

Therefore,

Volume = 3.14 × 8² × 19

Volume = 3.14 × 64 × 19

Volume = 3818.2 cubic feet rounded to the nearest tenth

6 0

3 years ago

Read this E[2X^2 â€" Y].

djyliett [7]

Looks like a badly encoded/decoded symbol. It's supposed to be a minus sign, so you're asked to find the expectation of 2X ² - Y.

If you don't know how X or Y are distributed, but you know E[X ²] and E[Y], then it's as simple as distributing the expectation over the sum:

E[2X ² - Y] = 2 E[X ²] - E[Y]

Or, if you're given the expectation and variance of X, you have

Var[X] = E[X ²] - E[X]²

→ E[2X ² - Y] = 2 (Var[X] + E[X]²) - E[Y]

Otherwise, you may be given the density function, or joint density, in which case you can determine the expectations by computing an integral or sum.

6 0

2 years ago

If anybody now this pls help my homework due TOMORROW

Nezavi [6.7K]

Answer:

Part A: D. $y = (x + 1)(x+3)\\$

Part B: C. $3x(x-3) = 0\\$

Step-by-step explanation:

For part A) we just have to plug in 0 for x and solve for y until we find the equation that says 3 is the value for y when x is 0. For purposes of speeding up the process the correct answer is D. I will show how to check for it now.

The equation: $y = (x + 1)(x+3)$

Now plug in 0 for x.

$y = (0 + 1)(0+3)\\$

Now solve.

y = (1)(3)

y = 3

This proves that this is the correct answer.

For part B) we just have to plug in the give values for x separately and check for each value of x that it equals 0. For the purpose of speeding up the process the correct answer is C. I will show how to check for it now.

The equation: $3x(x-3) = 0$