Answer:
Neither Troy nor Keith is correct.
Step-by-step explanation:
Neither Troy nor Keith is correct.
The value 0.9 is the same as the value 0.90.
The zeros after a decimal point are always insignificant unless they are followed by a number different from zero.
0.90 = 0.900 = 0.9000 = 0.90000 = ... = 0.9000000000
and all these can be easily written as 0.9, as the zeros after the decimal point do not change the value.
But 0.901, 0.9000004, 0.90002, and so on are all different, and the zeros are relevant, as they are followed by numbers different from zero.
Answer: A-(2,6)! :)
Explanation:
y < x^2 + 6
6 < 2^2 + 6
6 < 4 + 6
6 < 10 IT WORKS
y > x^2 - 4
6 > 2^2 - 4
6 > 4 - 4
6 > 0 IT WORKS
(Could I also get brainliest please?)
20 + 20 + 30 + 15 + 40 = 125
125/5= 25
25-15 = 10
Absolute deviation for 15 is 10
7X-4=6X-4-X
7X-6X+X=0
2X=0
X=0
No, they are both incorrect by my understanding of your question use the Pythagorean theorem a^2 + b^2 =c^, therefore, 7^2 +x^2 = 13^2 or 49+x=169 then solve normally 169-49=120 √120 =5
The answer is 5
