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Sphinxa [80]
3 years ago
15

What does 2+2 equal to​

Mathematics
2 answers:
Elena L [17]3 years ago
8 0

2+2=4 because you add it ok well bye :)

Mazyrski [523]3 years ago
5 0

Answer:

Step-by-step explanation:

1

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Evaluate square root of 16 minus x end root when x = 8.
My name is Ann [436]
\sqrt{16-x}
x=8
16-8=8
\sqrt{8}

Use a calculator to find the square root of 8.

7 0
3 years ago
Prove A-(BnC) = (A-B)U(A-C), explain with an example​
NikAS [45]

Answer:

Prove set equality by showing that for any element x, x \in (A \backslash (B \cap C)) if and only if x \in ((A \backslash B) \cup (A \backslash C)).

Example:

A = \lbrace 0,\, 1,\, 2,\, 3 \rbrace.

B = \lbrace0,\, 1 \rbrace.

C = \lbrace0,\, 2 \rbrace.

\begin{aligned} & A \backslash (B \cap C) \\ =\; & \lbrace 0,\, 1,\, 2,\, 3 \rbrace \backslash \lbrace 0 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace \end{aligned}.

\begin{aligned}& (A \backslash B) \cup (A \backslash C) \\ =\; & \lbrace 2,\, 3\rbrace \cup \lbrace 1,\, 3 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace\end{aligned}.

Step-by-step explanation:

Proof for [x \in (A \backslash (B \cap C))] \implies [x \in ((A \backslash B) \cup (A \backslash C))] for any element x:

Assume that x \in (A \backslash (B \cap C)). Thus, x \in A and x \not \in (B \cap C).

Since x \not \in (B \cap C), either x \not \in B or x \not \in C (or both.)

  • If x \not \in B, then combined with x \in A, x \in (A \backslash B).
  • Similarly, if x \not \in C, then combined with x \in A, x \in (A \backslash C).

Thus, either x \in (A \backslash B) or x \in (A \backslash C) (or both.)

Therefore, x \in ((A \backslash B) \cup (A \backslash C)) as required.

Proof for [x \in ((A \backslash B) \cup (A \backslash C))] \implies [x \in (A \backslash (B \cap C))]:

Assume that x \in ((A \backslash B) \cup (A \backslash C)). Thus, either x \in (A \backslash B) or x \in (A \backslash C) (or both.)

  • If x \in (A \backslash B), then x \in A and x \not \in B. Notice that (x \not \in B) \implies (x \not \in (B \cap C)) since the contrapositive of that statement, (x \in (B \cap C)) \implies (x \in B), is true. Therefore, x \not \in (B \cap C) and thus x \in A \backslash (B \cap C).
  • Otherwise, if x \in A \backslash C, then x \in A and x \not \in C. Similarly, x \not \in C \! implies x \not \in (B \cap C). Therefore, x \in A \backslash (B \cap C).

Either way, x \in A \backslash (B \cap C).

Therefore, x \in ((A \backslash B) \cup (A \backslash C)) implies x \in A \backslash (B \cap C), as required.

8 0
2 years ago
What is the measure of angle J in the triangle below? <br> A. 99<br> B. 42 <br> C. 9<br> D. 48
Leya [2.2K]
For this use the law of sines:
\sin( \alpha ) \div a = \sin( \beta ) \div b \\ \sin( \alpha ) \div 11 = \sin(103) \div 16
\frac{ \sin( \alpha ) }{11} = \frac{0.97}{16}
cross-multiply:
16×sin (J) = 11×0.97
sin(J) = 10.72/16
sin(J) = 0.67
hit the "arcsin" button on your calculator:
{ \sin}^{ - 1} (0.67) = 42.06 = 42.1 \: deg
therefore answer B. 42 is the correct answer!!
4 0
3 years ago
The difference of 2 squared numbers equals 53, what are the numbers​
Eva8 [605]

Answer:

  27, 26

Step-by-step explanation:

  27^2 -26^2 = 729 -676 = 53

If the numbers are integers, they must differ by an odd number. For some odd number k, we will have ...

  (x +k)^2 -x^2 = 53

  2xk +k^2 = 53

  x = (53 -k^2)/(2k)

  x = 53/(2k) -k/2

The second term is an odd multiple of 1/2. The first term will be an odd multiple of 1/2 only for k=1. For k = 1, we have ...

  x = (53 -1)/2 = 26

The two numbers are 26 and 27.

8 0
3 years ago
Simplify: 4 1/2<br> ÷ 2:
denis23 [38]

Answer:

9/4 = 2 1/4

Step-by-step explanation:

3 0
2 years ago
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