The function f(x) is vertically compressed to form g(x) while the function f(x) is vertically compressed and then reflected across the x-axis to form h(x)

<h3>How to compare both functions?</h3>

The functions are given as

f(x) =x^2

g(x) =3x^2

h(x) = -3x^2

Substitute f(x) =x^2 in g(x) =3x^2 and h(x) = -3x^2

g(x) =3f(x)

h(x) = -3f(x)

This means that the function f(x) is vertically compressed to form g(x)

Also, the function f(x) is vertically compressed and then reflected across the x-axis to form h(x)

See attachment for the functions g(x) and h(x)

Also, functions f(x) and g(x) have the same domain and range

While functions f(x) and h(x) have the same domain but different range

The complete table is:

x -2 -1 0 1 2

g(x) 12 3 0 3 12

h(x) -12 -3 0 -3 -12

Read more about function transformation at:

brainly.com/question/13810353

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4 0

1 year ago

A long distance calling plan charges 99 cents per minute for any call not exceeding 20 minutes in length and 7 cents for each ad

Ivanshal [37]

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3 0

2 years ago

Suppose f (x )right arrow 250 and g (x )right arrow 0 with g(x)greater than0 as x right arrow 5. Determine ModifyingBelow lim W

Rama09 [41]

Answer:

The limit is $\lim_{x \to 5} \frac{250}{0} = \infty$

Step-by-step explanation:

The equation given are

$f(x) \to 250$

and $g(x) \to 0$

with $g(x) > 0 \ as\ x ---> 5$

The objective is to obtain

$\lim_{x \to 5} \frac{f(x)}{g(x)}$

This mathematically evaluated as

$\lim_{x \to 5} \frac{250}{0}$

$= \lim_{x \to 5} \frac{250}{0} = \infty$

6 0

2 years ago