Through: (5,-3), slope=-1
1 answer:
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8y - 3 = 6y + 17
First, add 3 to both sides. / Your problem should look like: 8y = 6y + 17 + 3
Second, simplify 6y + 17 + 3 to 6y + 20. / Your problem should look like: 8y = 6y + 20
Third, subtract 6y from both sides. / Your problem should look like: 8y - 6y = 20
Fourth, simplify 8y - 6y to 2y. / Your problem should look like: 2y = 20
Fifth, divide both sides by 2. / Your problem should look like: y =
Sixth, simplify to 10. / Your problem should look like: y = 10
Answer: y = 10
First, add 3 to both sides. / Your problem should look like: 8y = 6y + 17 + 3
Second, simplify 6y + 17 + 3 to 6y + 20. / Your problem should look like: 8y = 6y + 20
Third, subtract 6y from both sides. / Your problem should look like: 8y - 6y = 20
Fourth, simplify 8y - 6y to 2y. / Your problem should look like: 2y = 20
Fifth, divide both sides by 2. / Your problem should look like: y =
Sixth, simplify
Answer: y = 10
- The information to complete the table is given below:
- Equation that shows the relationship between the cost per night C and the number of people staying in the chalet n: C= 4000-100(n-1)
An equation is a mathematical expression that contains an equals symbol. Equations often contain algebra. Algebra is used in math when you do not know the exact number in a calculation.
Given that:
Pules Rs 4000 per night but will decrease the amount by R100 per person occupying the chalet.
Number of People Cost per night
1 4000
2 3900
3 3800
4 3700
5 3600
6 3500
7 3400
8 3300
9 3200
10 3100
let C be cost per night and n be the number of people of staying in chalet.
equation: C= 4000-100(n-1)
for n=1: C= 4000- 0=4000
n=2, C= 4000-100(1)= 3900
The graph is attached below:
Learn more about equation here:
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