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Dafna11 [192]
3 years ago
11

(78 n + 42)^2, when n = 91

Mathematics
1 answer:
Sergio039 [100]3 years ago
7 0
So evaluate/subsitue
the equation becomes
(78 times 91+42)^2

pemdas
do what's inside the parenthasees first

start over
parenthasees
exponents
multiplication and division yes 78 times 91
addition  and subtraction so


78 times 91 is first
78 times 91=7098
addition
(7098+42)^2
(7140)^2

restart

parentasees simplified
exponents
7140^2=50,979,600
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