keeping in mind that any line parallel to MN will have the same exact slope as MN's.
![\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{6})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{0}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{0-6}{4-2}\implies \cfrac{-6}{2}\implies \cfrac{-3}{1}\implies -3~~\checkmark \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Bx_1%7D%7B2%7D~%2C~%5Cstackrel%7By_1%7D%7B6%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B4%7D~%2C~%5Cstackrel%7By_2%7D%7B0%7D%29%20%5C%5C%5C%5C%5C%5C%20slope%20%3D%20m%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%7B%20y_2-%20y_1%7D%7D%7B%5Cstackrel%7Brun%7D%7B%20x_2-%20x_1%7D%7D%5Cimplies%20%5Ccfrac%7B0-6%7D%7B4-2%7D%5Cimplies%20%5Ccfrac%7B-6%7D%7B2%7D%5Cimplies%20%5Ccfrac%7B-3%7D%7B1%7D%5Cimplies%20-3~~%5Ccheckmark%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
Answer: The answer is 2k-13 because I just did it.And i'm very good at math.
Step-by-step explanation:
Answer: 800 feet²
Step-by-step explanation:
Lets remove the brackets from the function's expression
A(x) = -2x²+80x
So we got the quadratic function and we have to find the x that corresponds to function's maximum. Let it be X max
As we know Xmax= (X1+X2)/2 , where X1 and X2 are the roots of the function A(x)
Lets find X1 and X2
x(80-2x)=0
x1=0 80-2*X2=0
x2=40
So Xmax= (0+40)/2=20
So Amax= A(20)= 20*(80-2*20)=20*40=800 feet²
Answer:
y = 6x + 1
Step-by-step explanation:
linear equations (straight line) are expressed in the following general form:
y = mx + b, where m is the gradient and b is the y-ordinate of the point where the line crosses the y-axis (called the y-intercept)
Given : m = 6
we realize that point (0,1) is actually on the y-axis (i.e x=0), therefore this is coincidentally the y-intercept. Hence b = 1
Therefore the whole equation is
y = 6x + 1
Answer:
mee two
Step-by-step explanation:
