
We know that,
- Pythagoras theoram is given by : p² + b² = h²
- In a Pythagoras triplet, the longest side represents the hypotenuse of the triangle.
Then,
We should check that, whether the sum of squares of the smaller sides will be equal to the square of the third side or not. Then, we can determine the above easily.
Sum of squares of smaller sides:
= 6² + 8²
= 36 + 64
= 100
Square of longer side:
= 10²
= 100
Sum of squares of smaller sides = Square of longer side. Hence, 6,8,10 are Pythagorean triplets.
And we are done! :D
⛱️ 
Answer:
h =
- r
Step-by-step explanation:
The question requires you to make h the subject of the formula.
S = 2πrh + 2πr²
subtract 2πr² on both sides.
S - 2πr² = 2πrh - 2πr² - 2πr²
S - 2πr² = 2πrh
Dividing both sides by 2πr
(S - 2πr²)/2πr = 2πrh/ 2πr
h =
- r
Sorry I do not know. Sorry to let you down
6(y-1)-9=-5(-3y+5)-3y
6y-6-9=15y-25-3y
6y-15=12y-25
+15. +15
6y=12y-25
+12y +12y
18y=-25
÷18. ÷18
y=-1.38
or -1 19/50
Answer:
=12
Step-by-step explanation:
7=3(0)-5
7=-5
7+5
=12
Im pretty sure this is the answer