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2 years ago

How do you divide 16divide 320?

Mathematics

2 answers:

bija089 [108]2 years ago

7 0

=1/20 or decimal 0.05

Aleksandr-060686 [28]2 years ago

5 0

Answer:

Ya can t at least I don't think you can

Step-by-step explanation:

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Answer the following function, algebra 1.

11111nata11111 [884]

Answer:

g(f(x)) = 1x² + 1

Step-by-step explanation:

We are given:
f(x) = x² - 1

g(x) = x + 2

And we want to find g(f(x)).

To do this, we substitute f(x) as x in x+2 (the expression that is equal to g(x)), as g(f(x)) is saying that f(x) is the value of x in g(x).

So, this will be:

g(f(x)) = x² - 1 + 2

Simplify

g(f(x)) = x² + 1

In your system, place 1 in front of x² - this is the coefficient of x², and also 1 after that - this is a constant.

4 0

1 year ago

24x^5-8x^4+12x^3-4x^2 / 4x^2

Margaret [11]

Answer:

The detailed process of simplification is :

Step-by-step explanation:

$\frac{24x^{5} - 8x^{4} + 12x^{3} - 4x^{2} }{4x^{2} }$

= $\frac{24x^{5} }{4x^{2} }$ - $\frac{8x^{4} }{4x^{2} }$ + $\frac{12x^{3} }{4x^{2} }$ - $\frac{4x^{2} }{4x^{2} }$ ..........................separate the terms

= 6 $x^{5-2}$ - 2 $x^{4-2}$ + 3 $x^{3-2}$ - 1 ................ subtract the power of x from denominator

= 6 $x^{3}$ - 2 $x^{2}$ + 3 $x$ -1

= 2 $x^{2}$ ( 3 $x$ -1 ) + (3 $x$ -1 )................................... Take (3 $x$ -1 ) common in (6 $x^{3}$ - 2 $x^{2}$ )

= (3 $x$ -1 ) (2 $x^{2}$ +1) .......................................Take (3 $x$ -1 ) common in whole equation

3 0

3 years ago

Write a x (-a)x 13 x a x (-a) x 13 in power notation

miss Akunina [59]

Answer:

$a\times (-a)\times 13\times a\times (-a)\times 13$ can be written in power notation as $a^{4}\times 13^{2}$

Step-by-step explanation:

The given expression

$a\times (-a)\times 13\times a\times (-a)\times 13$

Writing a\times (-a)\times 13\times a\times (-a)\times 13 in power notation:

Let

$a\times (-a)\times 13\times a\times (-a)\times 13$

= $[13\times13][(a\times (-a)\times a\times (-a)]$

$13\times13 = 13^{2}$ , $a\times a = a^{2}$ , $(-a)\times (-a) = (-a)^{2}$

So,

$=[13^{2}][a^2\times (-a)^2]$

$(-a)^2 = a^{2}$

So,

$=[13^{2}][a^2\times a^2]$

As ∵ $a^{m} \times a^{n}=a^{m+n}$

$=[13^{2}][a^{2+2}]$

As ∵ $a^{m} \times a^{n}=a^{m+n}$

$=13^{2}\times a^{4}$

$=a^{4}\times 13^{2}$

Therefore, $a\times (-a)\times 13\times a\times (-a)\times 13$ can be written in power notation as $a^{4}\times 13^{2}$

Keywords: power notation

Learn more about power notation from brainly.com/question/2147364

#learnwithBrainly

5 0

2 years ago

Write the equation of the line shown in the graph. Please help.

jeka57 [31]

Answer:

y = 3

Step-by-step explanation:

The y-coordinate of all points on the graph is 3.

The equation is y = 3

3 0

2 years ago

Read 2 more answers

Given a/b=x+5, solve for B

anygoal [31]

Answer:

Refer the attachment for the answer

Hope it helps

Please mark me as the brainliest

Thank you

7 0

3 years ago