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hichkok12 [17]
3 years ago
14

Help please if you can then thank you so much if you can't see number 4 and 5 then here.

Mathematics
2 answers:
sergij07 [2.7K]3 years ago
5 0

Answer:

2) A- 8h 15m

3) C- 6h 59m

4) A- 37m

5) B- 1h 2m


meriva3 years ago
3 0

Answer:

2.  8 hours and 15 mins

3. 7 hours 1 min

4. 37 mins

5. 1 hour 2 mins


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The clerk at the checkout counter earned $350 in 25 hours.
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Answer: 14 a hour

Step-by-step explanation:

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1/6 * 3/4<br> could be answers <br> 3/10<br> 1/6<br> 1/8 <br> 4/10
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A students' choir contains 25 children and only 5 of them play the piano. If a child is selected at random, what is the probabil
solniwko [45]

Answer:

probability that the child DOES NOT play the piano

P(E^{-})  =\frac{4}{5}

Step-by-step explanation:

A students' choir contains 25 children

n(S) =25

The number of students play the piano =5

Let 'E' be the event of the child play the piano so n(E) =5

The probability of that the child play the piano

 P(E) = \frac{n(E)}{n(S)}

 P(E) = \frac{5}{25}= \frac{1}{5}

Let 'E⁻ be the event of the child play does not play the piano

P(E^{-}) = 1- P(E)

P(E^{-}) = 1- \frac{1}{5} =\frac{4}{5}

<u>Conclusion</u>:-

probability that the child DOES NOT play the piano

P(E^{-})  =\frac{4}{5}

5 0
3 years ago
Find the domain in interval notation.
Nady [450]

Answer:

<em>x ∈ ( - ∞ , - 8 ) ∪ ( - 8 , 0 ) ∪ ( 0 , 8 ) ∪ ( 8 , ∞ ) </em>

Step-by-step explanation:

x³ - 64x = x( x² - 64 ) ≠ 0 ⇒ x ≠ 0 and x ≠ ± 8

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6 0
3 years ago
A random sample of math majors taking an introductory statistics course were surveyed after completing the final exam. They were
quester [9]

Answer:

E(X) =1 *\frac{1}{5} +2 *\frac{2}{5} +7*\frac{2}{5}= 3.8

Now we can find the second moment with this formula:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =1^2 *\frac{1}{5} +2^2 *\frac{2}{5} +7^2*\frac{2}{5}= 21.4

The variance would be given by:

Var(X) =E(X^2) -[E(X)]^2 = 21.4 -[3.8]^2 = 6.96

And the deviation would be:

Sd(X) =\sqrt{6.96}= 2.638

Step-by-step explanation:

For this case we have the following distribution given:

X      1      2      7

P(X) 1/5  2/5   2/5

We need to begin finding the mean with this formula:

E(X) = \sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(X) =1 *\frac{1}{5} +2 *\frac{2}{5} +7*\frac{2}{5}= 3.8

Now we can find the second moment with this formula:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =1^2 *\frac{1}{5} +2^2 *\frac{2}{5} +7^2*\frac{2}{5}= 21.4

The variance would be given by:

Var(X) =E(X^2) -[E(X)]^2 = 21.4 -[3.8]^2 = 6.96

And the deviation would be:

Sd(X) =\sqrt{6.96}= 2.638

7 0
3 years ago
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