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Kazeer [188]
2 years ago
10

Apples come in bags of 4. Oranges come in bags of 6. W What is the least number of bags of each a person has to buy to have the

same number of apples and oranges? Drag and drop a number into each box to correctly complete the statement That person needs to buy bags of apples and bags of oranges. 1 2 3 4 12 14. 24​
Mathematics
1 answer:
DochEvi [55]2 years ago
8 0

The least number of bags of apples a person has to buy is 3

The least number of bags of  oranges a person has to buy is  2

In order to determine the least bags that a person has to be buy to have the same number of apples and oranges, we have to determine the multiples of each day. The least common multiple of both numbers have to be determined

The multiple of a number is the number that is derived when a number is multiplied by an integer

Multiples of 4 = 4, 8, <u>12, </u>16, 20, 24, 32,36,40

Multiples of 6 = 6, 12, 18, 24, 30, 36, 48, 54, 60

The common multiples are 12, 24, 36

The least common multiple is 12.

The least number of bags of apples a person has to buy = 12/ 4 = 3

The least number of bags of oranges a person has to buy = 12 / 6 = 2

In order to determine the least number of bags to buy, determine the least common multiple of both numbers and divide it by the number of fruits in each bag.

A similar question was solved here: brainly.com/question/6949331?referrer=searchResults

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As a disclaimer, I can't say I'm completely confident in this answer. Use at own risk.

Formulas:

Year 1: 328,000 (sales) - 117,000 (expense) = 211,000 (profit)

Year 2: 565,000 (sales) - x (expense) = y (profit)

Net Profit: 211,000 + y = 113,000

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211,000 (profit y1) + 565,000 (sales y2) = 776,000

776,000 - 113,000 (net profit) = -663,000 (expenses)

Confirm:

Net Profit: 211,000 + y = 113,000 (listed in formulas, just a reminder)

Plug in: 565,000 (y2 sales) - 663,000 (our solution) = -98,000

211,000 (y1 net) + -98,000 (our plug in) = 113,000 (2 year net profit given to us)
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