Assume that
a and b = the two legs of the right triangle.
c = the hypotenuse.
The area of the right triangle is 750 yd², therefore
(1/2)*a*b = 750
ab = 1500 (1)
The perimeter is 150yd, therefore
a + b + c = 150 (2)
Let the side fenced with wood be a, at $5/yd. Sides b and c are fenced with steel at $10/y. The total cost is $1200, therefore
5a + 10b + 10c = 1200
or
a + 2b + 2c = 240 (3)
From (2), obtain
c = 150 - a - b (4)
Substitute (4) into (3)
a + 2b + 2(150 - a - b) = 240
-a + 300 = 240
a = 60
From (1), obtain
60b = 1500
b = 25
From (4), obtain
c = 150 - 60 - 25 = 65
Answer:
A. The length of the leg fenced with wood is 60 yd.
B. The length of the leg fenced with steel is 25 yd.
Answer: The answer should be 72
Explanation: Triangles add up to 180. The two bottom points are the same. So you would take 180 and subtract it by 36. That would give you 144. You would then take 144 and divide it by 2, because the two angles are the same and your only trying to find one.
Answer:
Is there a picture to go with it?
Step-by-step explanation:
Answer:
coefficent matrix
Step-by-step explanation:
P. 366
"If the column of constant terms is not included, the matrix reduces to that of the coefficent matrix of the system"
-1 -3 -1
9 -9 -1
-1 -3 4
10 is your answer!! hope this helps