What is the period of the function shown in the graph?

The cost (c) to hire a dog trainer is varies directly with the amount of time (h) in hours spent training the dog.

NNADVOKAT [17]

Answer:

Part A) The proportional equation is $c=55h$

Part B) 8 hours of training

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y/x=k$ or $y=kx$

Let

c -----> the cost to hire a dog

h ----> the amount of time in hours

The linear equation is equal to

$c=kh$

Sue spent $660 on 12 hours of obedience training for her dog Muffin

Find the value of k (constant of proportionality)

$k=y/x$

substitute the values

$k=660/12=55$

therefore

The linear equation is

$c=55h$

For $c=\$440$

Find the value of h

substitute in the equation and solve for h

$440=55h$

$h=440/55=8\ hours$

5 0

3 years ago

Please help with this:)

Nat2105 [25]

Answer:

$area = 2 \times 6 \times \pi = 12\pi$

6 0

3 years ago

The cost of four scarfs and six hats is $52. The cost of two hats is $1 more than the cost of one scarf. What are the costs of o

timurjin [86]

Four scarves and six hats is $52.00
4s+6h=52 

two hats is $1.00 more than the cost of one scarf. 
2h=1s+1 
2h=s+1 
s=2h-1 

substitute for s 
4s+6h=52 
4(2h-1)+6h=52 
8h-4+6h=52 
14h=56 
h=4 

s=2h-1 
s=8-1 
s=7 

a scarf cost $7 
a hat cost $4

8 0

4 years ago

Read 2 more answers

PLZ HELP ME ILL GIVE BRAINLIEST, ITS ON THIS LINK https://brainly.com/question/19931314

astra-53 [7]

Answer:

hm okay

Step-by-step explanation:

5 0

3 years ago

5. Write down the nth term of each of the following G.Ps

yawa3891 [41]

Answer:

1i) nth term = 12(-b/4)^(n-1)

ii) nth term = 3(-1/9)^(n-1)

2i) Sixth term= (-3b^5)/256

ii) Eight term = -1/1594323

Question:

The complete question as found on brainly (question-10746111):

Write down the nth term of each of the following G.Ps whose first two terms are given as follows. Also find the term stated besides each G.P.

i) 12,-3b,......sixth term

ii) 3,-1/3,..........;8th term?

Step-by-step explanation:

1) To solve terms involving Geometric progressions (GPs), we would first state the variables that are to be incorporated in the formula.

i) 12,-3b,......;sixth term

1st term = a= 12

r = common ratio = 2nd term /1st term

r = -3b/12 = -b/4

Then we would find the nth term

See attachment for details

ii) 3,-1/3,..........;8th term

1st term = a= 3

r = common ratio = 2nd term /1st term

r = (-⅓)/3 = (-⅓)(⅓) = -1/9

Then we would find the nth term

See attachment for details

2) we are to determine the sixth term in (i) and eight term in (ii)

See attachment for details

Sixth term= (-3b^5)/256

Eight term = -1/1594323

7 0

3 years ago