The answer to your question is 7.59 so shes right
1. The table has a constant of proportionality of 4, therefore, the perimeter and side length of squares are proportional.
2. Equation for the proportion is, y = 4x.
Perimeter = 48 cm.
<h3>What is the Equation of a Proportional Relationship?</h3>
The equation that defines a proportional relationship is, y = kx, where k is the constant of proportionality between variables x and y.
1. For the table given:
y = perimeter
x = side length
k = constant of proportionality = 8/2 = 16/4 = 24/6 = 4.
Since k is the same all through, the equation can be modelled as y = 4x, which means the perimeter and side length of squares are proportional.
2. Using the equation, y = 4x,the perimeter (y) of a square when its side length is 12 (x) is:
y = 4(12)
y = 48 cm.
The perimeter (y) of the square is: 48 cm.
Learn more about proportional relationship on:
brainly.com/question/15618632
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Well basically you just have to chose a number of sides for the side length of the square to be and move those many places to get another vertex of the square. For example if we have (-2,3) and we choose the side lengths to be 4 units than you could move 4 places up, down, left, or right to get the other vertices for the square
Hope that helps :)
Answer:
Step-by-step explanation:
We want to find the Riemann sum for 
with n = 6, using left endpoints.
The Left Riemann Sum uses the left endpoints of a sub-interval:
where 
.
Step 1: Find 
We have that 
Therefore, 
Step 2: Divide the interval ![\left[0,\frac{3 \pi}{4}\right]](https://tex.z-dn.net/?f=%5Cleft%5B0%2C%5Cfrac%7B3%20%5Cpi%7D%7B4%7D%5Cright%5D)
into n = 6 sub-intervals of length 
![a=\left[0, \frac{\pi}{8}\right], \left[\frac{\pi}{8}, \frac{\pi}{4}\right], \left[\frac{\pi}{4}, \frac{3 \pi}{8}\right], \left[\frac{3 \pi}{8}, \frac{\pi}{2}\right], \left[\frac{\pi}{2}, \frac{5 \pi}{8}\right], \left[\frac{5 \pi}{8}, \frac{3 \pi}{4}\right]=b](https://tex.z-dn.net/?f=a%3D%5Cleft%5B0%2C%20%5Cfrac%7B%5Cpi%7D%7B8%7D%5Cright%5D%2C%20%5Cleft%5B%5Cfrac%7B%5Cpi%7D%7B8%7D%2C%20%5Cfrac%7B%5Cpi%7D%7B4%7D%5Cright%5D%2C%20%5Cleft%5B%5Cfrac%7B%5Cpi%7D%7B4%7D%2C%20%5Cfrac%7B3%20%5Cpi%7D%7B8%7D%5Cright%5D%2C%20%5Cleft%5B%5Cfrac%7B3%20%5Cpi%7D%7B8%7D%2C%20%5Cfrac%7B%5Cpi%7D%7B2%7D%5Cright%5D%2C%20%5Cleft%5B%5Cfrac%7B%5Cpi%7D%7B2%7D%2C%20%5Cfrac%7B5%20%5Cpi%7D%7B8%7D%5Cright%5D%2C%20%5Cleft%5B%5Cfrac%7B5%20%5Cpi%7D%7B8%7D%2C%20%5Cfrac%7B3%20%5Cpi%7D%7B4%7D%5Cright%5D%3Db)
Step 3: Evaluate the function at the left endpoints
Step 4: Apply the Left Riemann Sum formula
