Answer:
The answer is
<h2>15v - 17</h2>
Step-by-step explanation:
3+ – 5(4+ – 3v) can be written as
3 - 5( 4 - 3v)
Expand and simplify
That's
3 - 20 + 15v
15v - 17
Hope this helps you
Answer:
Only equation 1 and 2 are equal.
Step-by-step explanation:
2 (x + 4)2 = 2
2( x² + 8x+ 16) = 2 Applying the square formula
2x² + 16x+ 32 = 2
2x² + 16x+ 32 -2= 0
2x² + 16x+ 30 = 0
2( x² + 8x+ 15)= 0 Taking 2 as common
x2 + 8x + 15 = 0------------eq 1
x2 + 8x + 15 = 0-------------eq 2
(x − 5)2 = 1
x²-10x+25= 1 Applying the square formula
x²-10x+25- 1= 0
x²-10x+24= 0-------------eq 3
x2 − 10x + 26 = 0 -------------eq 4
3(x − 1)2 + 5 = 0
3( x²-2x+1)+5= 0 Applying the square formula
3x²-6x+3+5= 0
3x²-6x+ 8= 0-------------eq 5
3x2 − 6x + 8 =1
3x2 − 6x + 8 -1=0
3x2 − 6x + 7 =0-------------eq 6
Answer:
The sum of a rational number and an irrational number is irrational." By definition, an irrational number in decimal form goes on forever without repeating (a non-repeating, non-terminating decimal). By definition, a rational number in decimal form either terminates or repeats.
Step-by-step explanation:
However, if the irrational parts of the numbers have a zero sum (cancel each other out), the sum will be rational. "The product of two irrational numbers is SOMETIMES irrational." Each time they assume the sum is rational; however, upon rearranging the terms of their equation, they get a contradiction (that an irrational number is equal to a rational number). Since the assumption that the sum of a rational and irrational number is rational leads to a contradiction, the sum must be irrational.
Cube root (27a^12)
Cube root 27 = 3 because
3 * 3 * 3 = 27
Cube root a^12 = a^4 because
a^4 * a^4 * a^4 = a^12
ANSWER
3a^4
