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2 years ago

7

A gardener is planting two types of trees: Type A is 4 feet tall and grows at a rate of 24 inches per year. Type B is 5 feet tal

l and grows at a rate of 21 inches per year. Algebraically determine exactly how many years it will take for these trees to be the same height.

1 answer:

goldenfox [79]2 years ago

4 0

It would take 5 yrs. for both trees to be the same height.

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Based on the table, which function models this situation?

alexdok [17]

Answer:

F(n) =-3n+24

Step-by-step explanation:

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2 years ago

REALLY APPRECIATE YOUR HELP<br><br>Given log x = 3 and log y = 2, prove that x^2 -7xy =3000y

anyanavicka [17]

Answer:

$if \: log(x ) = 3 \\ log_{10}(x) = 3 \\ {10}^{3} = x \\ therfore \to \: \boxed{x = {10}^{3} } \\ \\ if \: log(y ) = 2 \\ log_{10}(y) = 2 \\ {10}^{2} = y \\ therfore \to \: \boxed{y= {10}^{2} }$

Step-by-step explanation:

$x^2 -7xy =3000y \: then \to \\ x^2 =3000y + 7xy \\ {(10 ^{3} )}^{2} = 3000(10)^{2} + 7( {10}^{3} \times {10}^{2}) \\ {10}^{6} = 3000(10)^{2} + 7( {10}^{3} \times {10}^{2}) \\ {10}^{6} = 3000(10)^{2} + 7( {10}^{5} ) \\ {10}^{6} = 300000 + 700000 \\ \boxed{{10}^{6} = 1000000} \\ hence \: the \: equation \to \: x^2 -7xy =3000y \\ \boxed{ is \: corret}$

♨Rage♨

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2 years ago

Find the difference. (9/x^2-9x)-(6/x^2-81)

Sunny_sXe [5.5K]

The difference is $\frac{3 x+81}{x(x-9)(x+9)}$

Explanation:

The expression is $\left(\frac{9}{x^{2}-9 x}\right)-\left(\frac{6}{x^{2}-81}\right)$

Removing the parenthesis, we have,

$\left\frac{9}{x^{2}-9 x}\right-\left\frac{6}{x^{2}-81}\right$

Factoring the terms $x^{2}-9 x$ and $x^{2}-81$ , we get,

$\frac{9}{x(x-9)}-\frac{6}{(x+9)(x-9)}$

Taking LCM, we get,

$\frac{9(x+9)-6x}{x(x-9)(x+9)}}$

Simplifying the numerator, we get,

$\frac{9x+81-6x}{x(x-9)(x+9)}}$

Subtracting the numerator, we have,

$\frac{3 x+81}{x(x-9)(x+9)}$

Hence, the difference is $\frac{3 x+81}{x(x-9)(x+9)}$

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2 years ago

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noname [10]

Answer:

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Step-by-step explanation:

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2 years ago

Ugh! I don’t know how to do this. Someone please help!:) 15 Points for this one!

prisoha [69]

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3 years ago