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Kitty [74]
3 years ago
14

Ashley has two coupons for a phone.

Mathematics
1 answer:
Andreas93 [3]3 years ago
6 0
I think it’s Coupon A because the price should be 42.25 or about 42 dollars

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What’s this need help<br> asap !
Vsevolod [243]
I need points and i’m using this bc you didn’t even give an equation
5 0
2 years ago
Select all ordered pairs that satisfy the function of y=2/3x+1.
kvv77 [185]

Answer:

A.

Step-by-step explanation:

Plugging in all the values into the equation, only A holds a true statement.

5 0
3 years ago
Read 2 more answers
I NEED HELP! PLEASE HELP!
Amanda [17]

Answer:

2400 mm

Step-by-step explanation:

(80 x 60) - (60 x 40)

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3 years ago
If f(x)=7x-3, what is the value of x when f(x)=1
frosja888 [35]
Set up your equation:
1 = 7x - 3

Add 3 to both sides:
7x = 4

Divide both sides by 7:
x = 4/7

Hope this helps!
3 0
2 years ago
An aquarium with a square base has no top. There is a metal frame. Glass costs 8 dollars/m^2 and the frame costs 7 dollars/m. Th
Irina-Kira [14]
Given that the volume of the aquarium is 20m^3.

Volume = Area of Base x height

Area of Base = Volume / height = 20/h

Given that the aquarium has a square base.

Area of square = l^2

Thus, the length of the base of the aquarium is \sqrt{area \ of \ base} = \sqrt{ \frac{20}{h} }

The frame is to cover 8 sides with the length equal to the length of the base and 4 sides with the length of the height.

Thus, the total perimeter of the frame is given by 8\sqrt{\frac{20}{h}}+4h= \sqrt{64\left(\frac{20}{h}\right)}+4h = \sqrt{\frac{1,280}{h}}+4h

Area of the four side faces of the aquarium is 4 times the length of the base times the height = 4\times\sqrt{ \frac{20}{h} }\times h=\sqrt{16\left(\frac{20}{h}\right)h^2}=\sqrt{320h}

Total area to be covered by grass is the base and the four side faces and is given by \frac{20}{h}+\sqrt{320h}

Cost of the entire metal frame = 7\left(\sqrt{\frac{1,280}{h}}+4h\right)= \sqrt{49\left(\frac{1,280}{h}\right)}+7(4h) = \sqrt{\frac{62,720}{h}}+28h

Cost of the entire grass = 8\left(\frac{20}{h}+\sqrt{320h}\right)=\frac{160}{h}+\sqrt{64(320h)}=\frac{160}{h}+\sqrt{20,480h

Therefore, total cost in terms of the height, h, is given by

C=\sqrt{\frac{62,720}{h}}+28h+\frac{160}{h}+\sqrt{20,480h
3 0
3 years ago
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