Answer:
b.332.2
Step-by-step explanation:
<span>1. </span><span>4x –y = 8, the point (-4, 3)
Let’s say y = 0
=> 4x – 8
=> 4x / 4 = 8 /4
=> x = 2
So the point is (2 , 0).
Now, we have 2 forms, the (2,0) and the (-4, 3)
=> (y2 – y1)(x2 – x1) = m
=> m = (0 - 3)(2-(-4))
=> m = (0 - 3)(2+4)
=> m = (-3)(6)
=> m = -1/2
Thus,
y = -1/2x + a
=> 0 = -1 + a so a = 1
y = -x/2 + 1</span>
Answer:
In a rhombus, the diagonals bisect at right angles. That means half the diagonals form a right angle triangle then we can try the Pythagorean theorem. so -
one side of triangle = 6/2 =3 (half of the diagonal)
other side = 8/2 = 4
a^2 + b^2 = c2
3 ^2 + 4^2 = c^2
9+16 = c^2
c^2=25
c =
= 5
the hypothenus forms one side of the rhombus and here the hypothenus is 5, so the lenght of a side is 5 !