Answer:
Distance= 6.6 miles
Bearing= N 62.854°W
Step-by-step explanation:
Let's determine angle b first
Angle b=20° (alternate angles)
Using cosine rule
Let the distance between the liner and the port be x
X² =8.8²+2.4²-2(8.8)(2.4)cos20
X²= 77.44 + 5.76-(39.69)
X²= 43.51
X= √43.51
X= 6.596
X= 6.6 miles
Let's determine the angles within the triangle using sine rule
2.4/sin b = 6.6/sin20
(2.4*sin20)/6.6= sin b
0.1244 = sin b
7.146= b°
Angle c= 180-20-7.146
Angle c= 152.854°
For the bearing
110+7.146= 117.146
180-117.146= 62.854°
Bearing= N 62.854°W
Answer:
m<A = 70 deg
Step-by-step explanation:
The sum of the measures of the angles of a triangle is 180 deg. Add the three measures and set equal to 180. Solve for x. then use the value of x and the expression for m<A to find the measure of angle A.
m<A + m<B + m<C = 180
5x - 25 + 2x + 10 + 3x + 5 = 180
10x - 10 = 180
10x = 190
x = 19
m<A = 5x - 25 = 5(19) - 25 = 95 - 25 = 70
Answer: m<A = 70 deg
Answer:
False
Step-by-step explanation:
2x + y = 0
Try (1, -2)
2(1) + (-2) = 0
2 + (-2) = 0
0 = 0
The solution works on the first equation.
-x + 2y = 5
-(1) + 2(-2) = 5
-1 - 4 = 5
-5 = 5
The solution does not work in the second equation.
Answer: False
Hello,
I’m not sure how to answer your question because looks like you forgot to put an image of the shape your talking about.
Answer:
-4
Step-by-step explanation:
8-10 = -2
-2^2 = -4
