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aivan3 [116]
3 years ago
6

Gavin buys 89 blue pansies and 86 yellow pansies. He will plant the flowers in 5 rows with an equal number of plants in each row

. Draw a bar model to help you find how many plants will be in each row

Mathematics
2 answers:
Lemur [1.5K]3 years ago
8 0

Answer:

See figure attached.

Step-by-step explanation:

Gavin buys 89 blue pansies and 86 yellow pansies, then he buys 89 + 86 = 175 pansies. He will distribute them in 5 rows, then each row will have 175/5 = 35 pansies. The bar model consist of 5 rows each one of 35 units length.

ZanzabumX [31]3 years ago
6 0
  89
+86
_____
   175

what times what is 175?
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * 
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *

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se tiene que embaldosar el patio interior de un edificio con baldosas cuadradas de 30 cm de lado. El patio es rectangular y sus
shepuryov [24]

Answer:

40,000 baldosas

Step-by-step explanation:

Lo primero que debemos hacer aquí es calcular el área del patio rectangular.

El mejor enfoque para esto es convertir primero sus medidas a centímetros

Matemáticamente, 100 cm = 1 m, entonces 10 m se convierten en 1000 cm y 12 m se convierten en 1200 m.

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6 0
2 years ago
What is 3/16 of 200 written as a percentage
Georgia [21]

The expression 3/16 of 200 expression as a percentage is; 6.25%.

<h3>What is the value of 3/16 of 200 written as a percentage?</h3>

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Hence, the value 12.5 expressed as a percentage of 200 is;

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7 0
2 years ago
mr.browns salary is 32,000 and imcreases by $300 each year, write a sequence showing the salary for the first five years when wi
chubhunter [2.5K]

Hello!  

We have the following data:  

a1 (first term or first year salary) = 32000

r (ratio or annual increase) = 300

n (number of terms or each year worked)  

We apply the data in the Formula of the General Term of an Arithmetic Progression, to find in sequence the salary increases until it exceeds 34700, let us see:

formula:

a_n = a_1 + (n-1)*r

* second year salary

a_2 = a_1 + (2-1)*300

a_2 = 32000 + 1*300

a_2 = 32000 + 300

\boxed{a_2 = 32300}

* third year salary

a_3 = a_1 + (3-1)*300

a_3 = 32000 + 2*300

a_3 = 32000 + 600

\boxed{a_3 = 32600}

* fourth year salary

a_4 = a_1 + (4-1)*300

a_4 = 32000 + 3*300

a_4 = 32000 + 900

\boxed{a_4 = 32900}

* fifth year salary

a_5 = a_1 + (5-1)*300

a_5 = 32000 + 4*300

a_5 = 32000 + 1200

\boxed{a_5 = 33200}

We note that after the first five years, Mr. Browns' salary has not yet surpassed 34700, let's see when he will exceed the value:

* sixth year salary

a_6 = a_1 + (6-1)*300

a_6 = 32000 + 5*300

a_6 = 32000 + 1500

\boxed{a_6 = 33500}

* seventh year salary

a_7 = a_1 + (7-1)*300

a_7 = 32000 + 6*300

a_7 = 32000 + 1800

\boxed{a_7 = 33800}

*  eighth year salary

a_8 = a_1 + (8-1)*300

a_8 = 32000 + 7*300

a_8 = 32000 + 2100

\boxed{a_8 = 34100}

* ninth year salary

a_9 = a_1 + (9-1)*300

a_9 = 32000 + 8*300

a_9 = 32000 + 2400

\boxed{a_9 = 34400}

*  tenth year salary

a_{10} = a_1 + (10-1)*300

a_{10} = 32000 + 9*300

a_{10} = 32000 + 2700

\boxed{a_{10} = 34700}

we note that in the tenth year of salary the value equals but has not yet exceeded the stipulated value, only in the eleventh year will such value be surpassed, let us see:

*  eleventh year salary

a_{11} = a_1 + (11-1)*300

a_{11} = 32000 + 10*300

a_{11} = 32000 + 3000

\boxed{\boxed{a_{11} = 35000}}\end{array}}\qquad\checkmark

Respuesta:

In the eleventh year of salary he will earn more than 34700, in the case, this value will be 35000

________________________

¡Espero haberte ayudado, saludos... DexteR! =)

7 0
2 years ago
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