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lidiya [134]
3 years ago
10

2.0 hours and travels 5.0 km what's the average of speed?

Mathematics
1 answer:
disa [49]3 years ago
7 0
Average speed = 5/2 = 2.5 km/h
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A four person relay team completed a race in 72.4 seconds. On average what was each runner's time?
aleksley [76]
Each runners time would be an average of 18.1
72.4/4=18.1
4 0
3 years ago
A single batch of cookies requires two cups of sugar and three cups of flour. If more than one batch or a partial batch was made
HACTEHA [7]

Step-by-step explanation:

4 cup of sugar = 6 cup of flour

4.5 cup of sugar = 6.75 cup of flour

5 cup of sugar = 7.5 cup of flour

7.5 cup of sugar = 11.25 cup of flour

8 cup of sugar = 12cup of flour

hope it helps you

6 0
3 years ago
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5601 in scientific notation
Anna007 [38]
5.601 x 10^3

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8 0
3 years ago
Find the probability of rolling an odd sum or a sum less than 7 when a pair of dice is rolled
Nutka1998 [239]

Answer:

For the pairs that satisfy that the sum is less than 7 we have:

(1,1) (2,1) (1,2) (3,1) (2,2) (1,3) (4,1) (3,2) (2,3) (1,4) (5,1) (4.2) (3,3) (2,4) (1,5)

So we have a total of 15 pairs where the sum is less than 7

And for an odd sum we have the following pairs

(2,1) (1,2) (4,1) (3,2) (2,3) (1,4) (6,2) (5,2) (4,3) (3,4) (2,5) (1,6) (6,3) (5,4) (4,5) (3,6) (6,5) (5,6)

A total of 18 pairs and we have 6 pairs who are in both cases for the sum less than 7 and the sum an odd number that represent the intersection and using the total probability rule we got:

P = \frac{15+18-6}{36}= \frac{27}{33}= 0.818

Step-by-step explanation:

For this case when a pair of dice is rolled we have the following sample pace for the outcomes:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

We see 36 possible outcomes and we want to find how many of these pairs we got rolling an odd sum or a sum less than 7

For the pairs that satisfy that the sum is less than 7 we have:

(1,1) (2,1) (1,2) (3,1) (2,2) (1,3) (4,1) (3,2) (2,3) (1,4) (5,1) (4.2) (3,3) (2,4) (1,5)

So we have a total of 15 pairs where the sum is less than 7

And for an odd sum we have the following pairs

(2,1) (1,2) (4,1) (3,2) (2,3) (1,4) (6,2) (5,2) (4,3) (3,4) (2,5) (1,6) (6,3) (5,4) (4,5) (3,6) (6,5) (5,6)

A total of 18 pairs and we have 6 pairs who are in both cases for the sum less than 7 and the sum an odd number that represent the intersection and using the total probability rule we got:

P = \frac{15+18-6}{36}= \frac{27}{33}= 0.818

7 0
3 years ago
Help me anyone please
alexandr402 [8]
Question #1: Abby ended her walk at school.

Question #2: Abby and Bryan walk 9 blocks after school together to go to the grocery store and the park. After they leave the park, Bryan has to walk 5 blocks, and Abby has to walk 9 blocks to get home. Therefore Abby has to walk 4 more blocks than Bryan does.

Answer: 4 Blocks.
7 0
3 years ago
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