Evaluate each expression. 6! = 3!. 21 = 11

Mathematics

1 answer:

NNADVOKAT [17]4 years ago

8 0

Answer:

here we work with factorials, so if we have a whole number N, then:

N! = N*(N-1)*.....*2*1

then, for the given expressions we have:

1) 6! = 6*5*4*3*2*1 = 720.

2) 3!*21 = (3*2*1)*21 = 216

3) and the last expression seems incomplete, i guess this is:

11! = 11*10*9*8*7*6*5*4*3*2*1 = 39,916,800

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