Changes in the environment can lead to shortages of food due to no rain to water the plants for herbivores.
species that are used to favourable conditions will die due to environmental unfavourable conditions.
Circuit characteristics such as voltage, Contact resistance, and internal resistance of the body, Duration of the contract, Environmental conditions that affect the body's contact resistance, Pathway of the current through the body are not characteristic of contact with energized components that affect the severity of injury to a person in a shocking incident.
Sweating - Anything that increases the hydration of body tissues (such as sweating or being very young) makes a person a better conductor and therefore more likely to be injured in shock.
The main factors of energized components that influence the severity of an electric shock injury are 1) the amount of current flowing through the body, 2) the duration of the current flow, and 3) the path of the current through the body.
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Who is that? I can’t say I’ve heard that name before.
Answer: <u><em>A nation cannot have a comparative advantage in the production of every good.</em></u>
The principle of comparative advantage states that under free commerce, an representative will produce more of and consume less of a commodity for which they have a comparative advantage. Comparative advantage is the economic experience depicting the work increase from trade for individuals or nations, which originate from differences in their factor endowments or technological progress.
Answer:
The answer is below
Explanation:
The z core is used to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:
, x = raw score
Given that mean (μ) = 15 minutes per car, standard deviation (σ) = 2.4 minutes.
1) For x > 18:

From normal distribution table, P(x > 18) = P(z > 1.25) = 1 - P(z < 1.25) = 1 - 0.8944 = 0.1056
2) For x < 10:

From normal distribution table, P(x < 10) = P(z < -2.08) = 0.0188
3) For x > 12:

For x < 16:

From normal distribution table, P(12 < x < 16) = P(z < 0.42) - P(z < -1.25) = 0.6628 - 0.1056 = 0.5572