809.65 that is the answer i think
Answer:
Simple, no. This would not be enough.
Step-by-step explanation:
This is because you mentioned that there are 20 students and each of them needed 2 plates. So, there would need to be at least 40 plates. Forks seem irrelevant in this question but if the teacher has 8 plates in 1 box and another 8 in the second box, that would sum up to 16 plates that are available. And the fact that the box doesn't even include the other items, should hint the lack of items available for the students.
This question seemed worded differently. But tried my best. :)
Scale factor:
10/4= 2.5
X = 5 x 2.5 = 12.5
Y= 8/ 2.5 = 3.2
Z= 15/2.5 = 5
If you plug in the # the only one that is correct is y-8=-0.2(x+10)
