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andreev551 [17]
3 years ago
6

Fill in the blank with the best possible choice: the arac gene ___________. key points are underlined. a. will be transcribed by

rna polymerase to produce the arac mrna. the arac mrna will be translated by ribosomes to produce the arac protein, which is a bifunctional regulator for the gfp gene. b. will be transcribed by ribosomes to produce the arac protein, which will give bacterium ampicillin resistance. c. will be transcribed by ribosomes to produce the arac protein, which will glow under the uv light. d. will be translated by rna polymerase to produce the arac mrna. the arac mrna will be transcribed by ribosomes to produce the arac protein, which is a bifunctional regulator for the gfp gene.
Biology
1 answer:
Arisa [49]3 years ago
3 0
The correct answer is a: will be transcribed by RNA polymerase to produce the araC mRNA. The araC mRNA will be translated by ribosomes to produce the araC protein, which is a bifunctional regulator for the GFP gene.  
<span>
This is the correct answer because RNA polymerase transcribes and ribosomes translate which is not the case in other offered answers.</span>
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Answer:

a. 1/64 AATTDD

b. 1/64 aattdd

c. 8/64=1/8 AaTtDd

d. 2/64 = 1/32 AATTDd or aattDd or AAttDd or aaTTDd

Explanation:

<u>Available data:</u>

  • Flower position: Axial (A) is dominant to Terminal (a)
  • Stem length: Tall (T) is dominant to dwarf (t)
  • Seed shape: Round (R) is dominant to wrinkled (r)

<u>Cross</u>:

Parental) AaTtDd   x   AaTtDd

Knowing that these four genes assort independently, then we can infer that the F1 will have the next genotypic proportions for each gene:

  • AA= 1/4

       Aa =2/4

       aa = 1/4

  • TT = 1/4

        Tt = 2/4

         tt = 1/4

  • DD = 1/4

        Dd = 2/4

        dd = 1/4

<em>This is the same as developing a Punnett square for each gene separately.</em>

Knowing this, to get each of the mentioned genotypes for each trait, we must multiply their respective genotypic proportions, like this:

a. homozygous for the three dominant traits, AATTDD

   AA1/4 x TT 1/4 x DD 1/4 = AATTDD 1/64

b. homozygous for the three recessive traits, aattdd

   aa 1/4 x tt 1/4 x dd 1/4 = aattdd 1/64

c. heterozygous for all three characters, AaTtDd

   Aa 2/4 x Tt 2/4 x Dd 2/4 = AaTtDd 8/16=1/8

d. homozygous for axial and tall, heterozygous for seed shape. There are four possibilities, all of them with the same result:

AATTDd --> 1/4  x 1/4 x 2/4 = 2/64=1/32

aattDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

AAttDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

aaTTDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

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