Question

Given that f(x) = 2x2 − 96, find x.

Answer 1

Answer:

$x=\pm 4\sqrt{3}$

Step-by-step explanation:

We have been given an equation $f(x)=2x^2-96$. We are asked to solve for x.

To solve for x, we will equate our function with 0 as:

$2x^2-96=0$

$2x^2-96+96=0+96$

$2x^2=96$

$\frac{2x^2}{2}=\frac{96}{2}$

$x^2=48$

Upon taking square root of both sides, we will get;

$\sqrt{x^2}=\pm \sqrt{48}$

$x=\pm \sqrt{48}$

Factor out perfect square from square root:

$x=\pm \sqrt{16\cdot 3}$

$x=\pm \sqrt{4^2\cdot 3}$

$x=\pm 4\sqrt{3}$

Therefore, the solution of our given equation is $x=\pm 4\sqrt{3}$.

Answer 2

F(x)=2x(2)−96

Step 1: Add -4x to both sides.

xf+ −4x = 4x−96+ −4x

xf −4x= −96

Step 2: Factor out variable x.

x(f−4)= −96

Step 3: Divide both sides by f-4.

x(f−4)/ f−4 = −96/ f−4

x= −96/f−4

Answer:

x= −96/ f−4