A searchlight is shaped like a parabola. If the light source is located 3 feet from the base along the axis of symmetry and the
1 answer:
9514 1404 393
Answer:
8√3 ≈ 13.86 ft
Step-by-step explanation:
The light source is usually placed at the focus, so the focus-vertex distance is p=3 ft. The equation for the parabola with its vertex at the origin is ...
y = 1/(4p)x^2
y = 1/12x^2
The opening for some y-value extends ±x from the axis of symmetry, so is a total of 2x in width.
For y=4, the corresponding value of x is ...
4 = 1/12x^2
48 = x^2
√48 = x = 4√3
Then the width of the searchlight opening is ...
2(4√3 ft) = 8√3 ft ≈ 13.86 ft
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Answer:
• The base is 8 and the height is 6
Step-by-step explanation:
A rectangle has two dimensions:
The base, which is the distance between the points who have the same value of y.
The height, which is the distance between the points who have the same value of x.
Distance between 2 points:
Points (a,b) and (c,d).
I suppose there was a small typing mistake, as these points do not make a rectangle.
I will say that we have these following points:
L(0,6), M(8,6), N(8,0), O(0,0).
Base:
Same value of y.
L(0,6), M(8,6), or N(8,0) and O(0,0).
They will have the same result, will use the second.
The base is 8.
Height:
Same value of x.
L(0,6), O(0,0) or M(8,6) and N(8,0).
The height is 6.
So the correct answer is:
• The base is 8 and the height is 6